Question:
Consider ΔABC, whose vertices are A (2, 1), B (3, 3), and C (1, 6); let the line segment AC represent the base of the triangle.
(a) Find the equation of the line passing through B and perpendicular to the line AC
(b) Let the point of intersection of line AC with the line you found in part A be point D. Find the coordinates of point D.
Answer:


Step-by-step explanation:
Given




Solving (a): Line that passes through B, perpendicular to AC.
First, calculate the slope of AC

Where:
--- 
--- 
The slope is:



The slope of the line that passes through B is calculated as:
--- because it is perpendicular to AC.
So, we have:


The equation of the line is the calculated using:

Where:

--- 

So, we have:

Cross multiply




Make y the subject

Solving (b): Point of intersection between AC and 
First, calculate the equation of AC using:

Where:
--- 

So:



So, we have:
and 
Equate both to solve for x
i.e.


Collect like terms

Multiply through by 5

Collect like terms

Solve for x


Substitute
in 


Take LCM


Hence, the coordinates of D is:

Answer:
Wait... that's my name... whatever, here is the answer XD
Step-by-step explanation:
c+9.75=20.75 is the answer :D
Cost of his ticket is $20.75
Answer:
-8
Step-by-step explanation:
you need to rewrite it in y=mx+b form where b-is the y-intercept
y-4= -3(x+4)
distribute
y-4 = -3x-12
isolate y
y= -3x-8
compare this with the y=mx+b so y-intercept is -8
Answer: The perimeter of the new triangle is 16 times the perimeter of the original triangle.
Step-by-step explanation: