PLEASE HELP!! Points A, B, and P are collinear on segment AB, and AP: AB = 1/4. A is located at (8,4) and B is located at (4,12)
. What are the x and y coordinates of point P?
1 answer:
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Answer:
<h2>√34sin(x + 0.33π)</h2>Step-by-step explanation:
The general form of the equation acosx + bsinx = Rsin(x + e) where R is the resultant of the constants 'a' and 'b' and e is the angle between them.
R = √a²+b²
Given the function f(x) = 3 cos x + 5 sin x, comparing with the general equation;
a = 3, b = 5
R = √3²+5²
R = √9+25
R =√34
in radians;
3 cos x + 5 sin x = √34sin(x + 0.33π)