Circumference = square root (Area * 4 * PI)
circumference = square root (
<span>
<span>
<span>
452.3893421169
</span>
</span>
</span>
* 4 * PI )
<span>circumference = square root (
5,684.8921350275)
</span>circumference =
<span>
<span>
<span>
75.3982236862
</span>
</span>
</span>
Hey there,
The slope is the rise over the run of a line right?
And the formula is y2-y1 as the numerator and x2-x1 as the denominator.
So in this case the two xs are 1 and 2 right?
And the denominator is the second denominator is the second x minus the first x right?
In this case the second x is 2 roght?
And the first x is 1.
So it’s 2-1 which is 1.
So the answer is x2-x1 which is 1
Hope this helps
Answer:
3
Step-by-step explanation:
- 5x - 6 = 3x - 0
- 5x - 6 + 6 = 3x + 6
- 5x = 3x + 6
- 5x - 3x = 3x + 6 - 3x
- 2x = 6
- 2x / 2 = 6 / 2
- X = 3
Using y to represent number of bottles filled in x minutes, y = 250x.
This is rather basic, and I urge you to think about it so that it's very clear to you, and you will be able to do similar problems on your own in the future.
The graph will be a straight line passing through the origin (0,0).
Answer:
![I=\frac{x^3}{3(25x^2+1)^{3/2}}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7Bx%5E3%7D%7B3%2825x%5E2%2B1%29%5E%7B3%2F2%7D%7D)
Step-by-step explanation:
(a)
![5x=tan{\theta}\\x = \frac{\tan{\theta}}{5}\\dx=\frac{1}{5}\sec^2{\theta}d\theta\\](https://tex.z-dn.net/?f=5x%3Dtan%7B%5Ctheta%7D%5C%5Cx%20%3D%20%5Cfrac%7B%5Ctan%7B%5Ctheta%7D%7D%7B5%7D%5C%5Cdx%3D%5Cfrac%7B1%7D%7B5%7D%5Csec%5E2%7B%5Ctheta%7Dd%5Ctheta%5C%5C)
![I=\frac{1}{125}\int\frac{tan^2{\theta}sec^2{\theta}}{(tan^2{\theta}+1)^{5/2}}d\theta](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B125%7D%5Cint%5Cfrac%7Btan%5E2%7B%5Ctheta%7Dsec%5E2%7B%5Ctheta%7D%7D%7B%28tan%5E2%7B%5Ctheta%7D%2B1%29%5E%7B5%2F2%7D%7Dd%5Ctheta)
![I=\frac{1}{125}\int\frac{tan^2{\theta}sec^2{\theta}}{sec^5{\theta}}d\theta](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B125%7D%5Cint%5Cfrac%7Btan%5E2%7B%5Ctheta%7Dsec%5E2%7B%5Ctheta%7D%7D%7Bsec%5E5%7B%5Ctheta%7D%7Dd%5Ctheta)
![I=\frac{1}{125}\int\frac{tan^2{\theta}}{sec^3{\theta}}d\theta](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B125%7D%5Cint%5Cfrac%7Btan%5E2%7B%5Ctheta%7D%7D%7Bsec%5E3%7B%5Ctheta%7D%7Dd%5Ctheta)
![I=\frac{1}{125}\int\sin^2{\theta}{cos{\theta}}d\theta](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B125%7D%5Cint%5Csin%5E2%7B%5Ctheta%7D%7Bcos%7B%5Ctheta%7D%7Dd%5Ctheta)
![I=\frac{1}{125}\int\sin^2{\theta}d\sin{\theta}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B125%7D%5Cint%5Csin%5E2%7B%5Ctheta%7Dd%5Csin%7B%5Ctheta%7D)
![I=\frac{1}{125}\frac{1}{3}sin^3{\theta}}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B125%7D%5Cfrac%7B1%7D%7B3%7Dsin%5E3%7B%5Ctheta%7D%7D)
![I=\frac{1}{125}\frac{1}{3}(\frac{5x}{\sqrt{25x^2+1})})^3](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B125%7D%5Cfrac%7B1%7D%7B3%7D%28%5Cfrac%7B5x%7D%7B%5Csqrt%7B25x%5E2%2B1%7D%29%7D%29%5E3)