Which of the following is true about so4^2-

The first animal cloned by nuclear transfer was a _____ named Dolly.

kifflom [539]

<span>In the sentence "The first animal cloned by nuclear transfer was a _____ named Dolly", the word that correctly completes the sentence is sheep. A sheep named Dolly is the first animal cloned from an adult somatic cell by nuclear transfer. She was cloned at the Roslin Institute of the University of Edinburgh, Scotland, in 1996. There she died in 2003.</span>

6 0

3 years ago

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Can someone please help me!! What are the parts of a Bunsen burner if possible add a picture and name please thanks

borishaifa [10]

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>BUNSEN BURNER:</h2>

Bunsen burner is an instrument which is used as a source of heat using natural gas or petrol. It is used for the heating, sterlization, and combustion. Bunsen burner is named after its inventor Robert bunsen.

<h2>____________________________________</h2><h3>Mechanism:</h3>

Burner provide a single, continuous flame by mixing gas with air in a controlled fashion. The ratio of gas to air that is mixed together can be manually adjusted, allowing the user to control the intensity, temperature, and size of the flame.

<h2>____________________________________</h2><h3>PICTURE IS ATTACHED BELOW</h3><h2>____________________________________</h2><h2>Best Regards!</h2><h2>'Borz'</h2>

3 0

3 years ago

Which term refers to the speed at which reactants are converted into products?

liberstina [14]

Reaction rate , forsure

8 0

4 years ago

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All organic compounds contain ______, hydrogen, and usually oxygen. nitrogen. phosphorus. sulfur carbon.

Murrr4er [49]

Carbon is the answer. all hydrocarbures have to contain carbon.

4 0

3 years ago

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

Len [333]

Answer:

a. 1875 nm

b. 4051 nm

c. 1282 nm

These all are infrared electromagnetic radiation.

Explanation:

Our strategy here is to utilize the Rydberg equation for hydrogen atom electronic transition.

1/λ = Rh x (1/n₁² - 1/n₂²) where λ is the wavelength

Rh is Rydberg constant

n₁ and n ₂ are the energy levels ( n₁ < n₂ )

Now lets star the calculations.

a. n₁ = 3, n₂ = 4

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/4²) = 5.333 x 10⁵/m

λ = 1/(5.333 x 10⁵ /m) = 1.875 x 10⁻⁶ m

Converting λ to nanometers:

1.875 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1875 nm

b. n₁ = 4, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/4² - 1/5²) = 2.468 x 10⁵/m

λ = 1/(2.468 x 10⁵/m) = 4.051 x 10⁻⁶ m

4.051 x 10⁻⁶ m x (1 x10⁹ nm/m) = 4051 nm

c. n₁ = 3, n₂ = 5

1/λ = 1.097 x 10⁷ /m x (1/3² - 1/5²) = 7801 x 10⁵/m

λ = 1/(7801 x 10⁵/m) = 1282 x 10⁻⁶ m

1282 x 10⁻⁶ m x (1 x10⁹ nm/m) = 1282 nm

All of these transitions fall in the infrared region of the spectrum.

8 0

3 years ago