Its electronic confuguration is 2.8.6 so it occupies 3 shells.
Answer:
2.85moles of oxygen gas
Explanation:
Given parameters:
Volume of oxygen gas = 63.8L
Unknown:
Number of moles = ?
Solution:
We assume that the gas is under standard temperature and pressure. To find the number of moles, use the expression below:
1 mole of a gas at STP occupies a volume of 22.4L
So;
63.8L of oxygen gas will take up a volume of
= 2.85moles of oxygen gas
During the transamination process, the enzyme transaminases use Pyridoxal pyrophosphate as a cofactor.
All transamination reactions, as well as several amino acid oxylation and deamination processes, involve the coenzyme pyridoxal phosphate. The aminotransferase enzyme's epsilon-amino group of a particular lysine group forms a Schiff-base bond with the aldehyde group of pyridoxal phosphate.
The epsilon-amino group of the lysine residue in the active site is replaced by the alpha-amino group of the amino acid substrate. The ensuing intermediate, a quinoid, undergoes deprotonation to become an aldimine, which is then protonated to become a ketimine by accepting a proton in a different position. Ketamine undergoes hydrolysis, leaving the amino group on the protein complex intact.
Know more about Pyridoxal pyrophosphate at:
brainly.com/question/14117818
#SPJ4
Answer:
1. More data should be collected to get a more reliable average
2. A boiling point at 1.5 atmospheres could be predicted fairly well
3. The actual boiling point is probably between 34 C and 40 C
4. By taking 10 measurements of each of the five liquids and finding an average
5. The thermometer being used might need to be recalibrated
Explanation:
Took the quick check
Answer:
here is where you can buy it
https://www.walmart.com/ip/Product-Of-Hunts-Tomato-Paste-Can-Count-1-Tomato-Paste-Grab-Varieties-Flavors/850453511?wmlspartner=wlpa&selectedSellerId=4648&&adid=22222222228000000000&wl0=&wl1=g&wl2=m&wl3=42423897272&wl4=aud-430887228898:pla-51320962143&wl5=9012391&wl6=&wl7=&wl8=&wl9=pla&wl10=115056687&wl11=online&wl12=850453511&veh=sem&gclid=Cj0KCQjw9ZGYBhCEARIsAEUXITUEOCgO6I5Xsg6DjNJSFFzf6pLMzFzhjW7WipqMInuuYo8EfjNoRAkaAp17EALw_wcB&gclsrc=aw.ds
