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Ainat [17]
3 years ago
6

Mike had a jar of nickels that had five more nickels than he originally thought. If the total amount of nickels was $4.35, how m

any nickels did Mike think he had originally?
Mathematics
2 answers:
aivan3 [116]3 years ago
3 0
A nickel is worth 5 cents. So if he has 5 nickels extra. They are worth 25 cents. Subtract 0.25 from 4.35 and you get 4.10. Now all you have to do is divide  4.10 by 0.05, which is a nickel. The answer is "Mike thought he had 82 nickels"
Tamiku [17]3 years ago
3 0
$4.10, five nickels is eqivalent to 5 cents per nickel. therefore 5 centsx5 nickels=25 cents(the amount more than he thought was there). next you subract the amount extra from the amount total to get the answer
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M. Score: 0 of 1 pt
beks73 [17]

Answer:

  3×5×53

Step-by-step explanation:

You can use divisibility rules to find the small prime factors.

The number ends in 5, so is divisible by 5.

  795/5 = 159

The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.

  159/3 = 53 . . . . . a prime number,* so we're done.

795 = 3×5×53

_____

* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.

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3 years ago
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ladessa [460]

Answer:

113.44

Step-by-step explanation:

It can emulate the BIOS and many games at very slow speeds but is sometimes faster than Cxbx with acceptable graphics

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3 years ago
Look at the graph. which equation represents the graph?
Svetllana [295]
The correct answer is A
4 0
2 years ago
What is 9.5% in a decimal
Delvig [45]
Percentage means 'out of 100 100 '. Convert the decimal number to a fraction by shifting the decimal point in both the numerator and denominator. Since there is 1 1 number to the right of the decimal point, move the decimal point 1 1 place to the right.
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3 years ago
Read 2 more answers
How would you solve these 2 maths problems?
sweet-ann [11.9K]

Answer:

see explanation

Step-by-step explanation:

(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

compare with

x³ + 2x² - 3x + 4

x² terms

a - 2 = 2 ( add 2 to both sides )

a = 4

x terms

b - 2a = - 3 ← substitute a = 4

b - 8 = - 3 ( add 8 to both sides )

b = 5

constant terms

- 2b + c = 4 ← substitute b = 5

- 10 + c = 4 ( add 10 to both sides )

c = 14

Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = (-2)^{4} + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

- 8a + 4b + 56 = 0

- 8a + 4b = - 56 → (1)

and

g(- 2) = (-2)^{4} + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

b = - 28

Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

5 0
3 years ago
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