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Juliette [100K]
3 years ago
15

What are some temperature change chemica reaction equations ?

Chemistry
1 answer:
Zinaida [17]3 years ago
7 0

Answer:

The heating and melting of wax

Explanation:

When a candle is burned the wax heats up, but when cooled it hardens and cannot be put back into it original form.

Hope this helps

Please mark me as Brainliest

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Describe, in detail, how to make 3.0 liters of a 0.98 molar HCl solution from a 10.5 molar HCl stock solution.
Dmitrij [34]
In order to solve this question, you use the formula C1V1=C2V2; C1 and V1 represent the concentration and volume of the starting solution respectively, and C2 and V2 represent the concentration and volume of the final solution respectively.

In this case, C1 is 10.5, V1 is unknown, C2 is 0.98 and V2 is 3 liters.
(10.5)(x)=(0.98)(3) (divide both sides by 10.5)
X=0.28 L

This means that you will use 0.28 L of the 10.5 M solution and 2.27 L (3 L-0.28 L) of water to make 3 L of a 0.98 M solution.

Hope this helps

8 0
3 years ago
Solid carbon and oxygen gas react to yield carbon dioxide gas. write the following balanced chemical equation. please help
devlian [24]
I believe that is the answer

3 0
3 years ago
SEP Analyze Data Use graphing software or draw a graph from the data in the table. Label "Heat input (joules)" on the y-axis and
galben [10]

The characteristics of the graphic representation are to find the scales and make the best graphic, in the attachment we have the points plotted

The graphical representation is one of the best methods to see the relationships between groups of data and to be able to find the functional relationships between them.

In this case, it is requested to make a scatter plot where the measured temperature is placed on the x-axis and the heat on the y-axis.

In the attachment we can see a graph with the requested data, the most important part of finding these graphs is looking for the scales

x-axis

          scale x = \frac{\Delta Values}{paper length}

y-axis

          scale y = \frac{\Delta Values}{paper \ lengthy}

In general, the paper is 20 x 30 cm, we select the shortest part as the x axis

         scale x = \frac{50-30}{20}

         scale x = 1º  \frac{ C}{cm \ peper}  

         

Let's find the scale on the axis and the maximum value is 54000 and the minimum value is 3800, as the minimum value is much less than the maximum value, let's set this value to zero

         scale y = \frac{54000-0}{30}

         scale y = 1800  \frac{j}{cm \ paper}

To facilitate marking the values, we select a slightly larger scale,

Selected scale

           scale y = 2000 \frac{j}{cm \ paper}

Let's mark the points.

From observing these graph we see;

  • The relationships are linear
  • For the same material the amount of heat necessary to reach the same temperature is proportional to the mass of the material

Using the characteristics of the graphical representation, it is possible to find the scales and make the best graph

Learn more here: brainly.com/question/12511806

6 0
3 years ago
Which expression represents the concentration of OH– ions in solution? a. [OH–]  10–14 b. 10–14  [H3O+] c. 10–14  [H3O+] d. 1
7nadin3 [17]

Answer:

10^-14 / [H3O+]

Explanation:

Hydronium (H3O+) and hydroxide ions (OH-) are both present in pure water and in all aqueous solutions.

Their respective concentrations in water are 10^-7 M each and are inversely proportional to each other as given by the ion product of water, Kw.

Kw = [H3O+][OH−]

Where Kw = 1.0 * 10^-14,

[H3O+] = concentration of hydronium ions

[OH-] = concentration of hydroxide ions

Therefore, [OH-] = Kw / [H3O+]

[OH-] = 10^-14/[H3O+]

7 0
3 years ago
Rank the following aqueous solutions in order of increasing<br> (c) freezing point;
saveliy_v [14]

0.01 m AgNO_{3} < 0.03 m CuSO_{4}< 0.04 m urea

As molal concentration rises, so does freezing point depression. It can be expressed mathematically as ΔTf = Kfm.

<h3>What is Colligative Properties ?</h3>
  • The concentration of solute particles in a solution, not the composition of the solute, determines a colligative properties .
  • Osmotic pressure, boiling point elevation, freezing point depression, and vapor pressure reduction are examples of ligand-like properties.
<h3>What is freezing point depression?</h3>
  • When less of another non-volatile material is added, the temperature at which a substance freezes decreases, a process known as Freezing-point depression.
  • Examples include combining two solids together, such as contaminants in a finely powdered medicine, salt in water, alcohol in water.
  • An significant factor in workplace safety is freezing points.
  • If a substance is kept below its freezing point, it may become more or less dangerous.
  • The freezing point additionally offers a crucial safety standard for evaluating the impacts of worker exposure to cold conditions.

Learn moree about Colligative Properties here:

brainly.com/question/10323760

#SPJ4

5 0
2 years ago
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