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Law Incorporation [45]
3 years ago
7

Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h

as carbon tetrachloride as the solvent. Determine that molal concentration, m (or b), and boiling point, Tb.benzene boiling point=80.1 Kb=2.53carbon tetrachloride boiling point=76.8 Kb=5.03
Chemistry
1 answer:
Gnoma [55]3 years ago
6 0

Explanation:

We know that relation between change in temperature and molality is as follows.

           \Delta T = m \times k_{b}

And, boiling point of a solution is calculated as follows.

 Boiling point of a solution = Boiling point + \Delta T (k_{c} \times m)

For benzene solution, the boiling point is 80.1 + 2.53m.

For CCl_{4} solution, the boiling point is 76.8 + 5.03m

Now, equating the boiling point of both the solutions as follows.

          80.1 + 2.53m = 76.8 + 5.03m    

                3.3 = 2.5 m

               m = 1.32 mol of solute per kg of solvent

Therefore, the boiling point will be calculated as follows.

             80.1 + 2.53m

         80.1 + 2.53 \times 1.32      

          = 83.43^{o}C

Thus, we can conclude that molal concentration (m) is 1.32 and boiling point is 83.43^{o}C.          

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