For the equation:
-1=5 x^2 - 2 x
5 x^2 - 2 x + 1 = 0, then we substitute: a=5, b=-2, c =1
to discriminant formula: D= b^2 - 4 a c = (-2)^2 - 4 * 5 * 1 = 4 - 20 = - 16
Answer:
The discriminant is equal to -16 which means the equation has no real number solutions.
Answer:
<h2>The function has vertical asymptotes when x = 0, x = 3, and x = 5.</h2>
Step-by-step explanation:
The given rational function has vertical asymptotes. Remember that an asymptote is placed when the function has undetermined results, when we give a <em>x-value </em>and the <em>y-value </em>cannot be determined, there we say exists an asymptotes, which is a punctual line that represents a discontinuation of the graph, the trace cannot cross that asymptote, it divide the whole function graph.
So, in this case we have to undetermined results, when x = 0, x = 3, and x = 5, this means that in those values, there are asymptotes.
1.
Let w be the number of weeks it takes for Konrad to have more than $72.
The equation we can derive is 57 + 3w > 72.
Then solve:
57 + 3w > 72
3w > 15
w > 5
Then w must be 6, which is the next number greater than 5.
2.
Let w be the number of weeks it takes Omar to have enough money for the car.
The equation we can derive is 1800 + 35w 2150.
Then solve:
1800 + 35w 2150
35w 350
w 10
Then w must be 10.
-70
Some actually if it were y=mx+b then it would be the opposite. It would turn positive but I don’t think this one turns like that. I think it’s just -70