Answer:
The pressure of CO2 at the equilibriumis 0.185 atm
Explanation:
Step 1: Data given
The value of Kp at that temperature is 0.242
FeO was initially in a container with CO at a pressure of 0.95 atm
Step 2: The balanceequation
FeO(s) + CO(g) ⟷ Fe(s) + CO2(g)
Step 3:The initial pressure
pCO = 0.95 atm
pCO2 = 0 atm
Step 4: The pressure at the equilibrium
pCO = 0.95 - x atm
pCO2 = X atm
Step 5: Calculate Kp
Kp = pCO2 / pCO
0.242 = X / (0.95 - X)
X = 0.185
pCO = 0.95 - 0.185 = 0.765 atm
pCO2 = 0.185 atm
The pressure of CO2 at the equilibriumis 0.185 atm
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The answer of the question is mixture
Answer:
40.03g/mole
Explanation:
Given parameters:
Mass = 42.10 g/mole and abundance = 93.50%
Mass = 8.30 g/mole and abundance = 6.200%
Mass = 50.40 g/mole and abundace = 0.3000%
Find;
Average atomic mass = ?
Solution:
Average atomic mass = sum (mass x abundance)
Average atomic mass = (
) + (
x 8.3) + (
)
= 39.36g/mole + 0.52g/mole + 0.15g/mole
= 40.03g/mole
Answer:
C is the reaction intermediate.
Explanation:
A reaction intermediate is a molecular structure that is formed during the reaction but then is converted in the final products.
Usually, these reaction intermediates are unestable and, for that reason, the lifetime of these structures is low.
In the reaction, you can see in the first step C is produced, but also, in the second step reacts producing D. As is produced and, immediately consumed,
<h3>C is the reaction intermediate.</h3>