Answer:
67.9375
Step-by-step explanation:
x+15=19
x=19-15=4
x^3-x^-2+16x^-1 = 4^3-4^-2+16(4)^-1=67.9375
Answer:4p-7=13
Step-by-step explanation:combine like terms
Answer:
![L_1 = 4](https://tex.z-dn.net/?f=%20L_1%20%3D%204)
And ![L_2 = 3 +4 = 7](https://tex.z-dn.net/?f=%20L_2%20%3D%203%20%2B4%20%3D%207)
Step-by-step explanation:
For this case we assume that for the first square we have the following dimensions:
![A_1 = L^2_1](https://tex.z-dn.net/?f=%20A_1%20%3D%20L%5E2_1)
And we know that:
![L_2 = 3 + L_1](https://tex.z-dn.net/?f=%20L_2%20%3D%203%20%2B%20L_1)
And the area for the second square would be:
![A_2 = L^2_2 = (3+L_1)^2 = 9 + 6L_1 + L^2_1](https://tex.z-dn.net/?f=%20A_2%20%3D%20L%5E2_2%20%3D%20%283%2BL_1%29%5E2%20%3D%209%20%2B%206L_1%20%2B%20L%5E2_1)
And we know that the sum of areas is 65 so then we have this:
![A_1 + A_2 = 65](https://tex.z-dn.net/?f=%20A_1%20%2B%20A_2%20%3D%2065)
And replacing we got:
![L^2_1 + 9 + 6L_1 + L^2_1 = 65](https://tex.z-dn.net/?f=%20L%5E2_1%20%2B%209%20%2B%206L_1%20%2B%20L%5E2_1%20%3D%2065)
![2L^2_1 +6L_1 - 56=0](https://tex.z-dn.net/?f=%202L%5E2_1%20%2B6L_1%20-%2056%3D0)
We can divide the last expression by 2 and we got:
![L^2_1 + 3L_1 -28=0](https://tex.z-dn.net/?f=%20L%5E2_1%20%2B%203L_1%20-28%3D0)
And we can factorize the last expression like this:
![(L_1 + 7) (L_1 -4) =0](https://tex.z-dn.net/?f=%20%28L_1%20%2B%207%29%20%28L_1%20-4%29%20%3D0)
And we have two solutions for
and we got:
![L_1 = 4, L_1 = -7](https://tex.z-dn.net/?f=%20L_1%20%3D%204%2C%20L_1%20%3D%20-7)
Since the length can't be negative we have this:
![L_1 = 4](https://tex.z-dn.net/?f=%20L_1%20%3D%204)
And ![L_2 = 3 +4 = 7](https://tex.z-dn.net/?f=%20L_2%20%3D%203%20%2B4%20%3D%207)
Answer:
cos 41°
Step-by-step explanation:
![\sin 49 \degree = \cos(90 \degree - 49 \degree) = \cos41 \degree \\ \\ \huge {\boxed{\red{ \bold{ \therefore \: \sin 49 \degree }}= \purple{ \bold{\cos 41 \degree}}}}](https://tex.z-dn.net/?f=%20%5Csin%2049%20%20%5Cdegree%20%3D%20%20%5Ccos%2890%20%5Cdegree%20-%2049%20%5Cdegree%29%20%3D%20%20%5Ccos41%20%5Cdegree%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%7B%5Cboxed%7B%5Cred%7B%20%5Cbold%7B%20%20%5Ctherefore%20%5C%3A%20%20%5Csin%2049%20%20%5Cdegree%20%7D%7D%3D%20%20%20%5Cpurple%7B%20%5Cbold%7B%5Ccos%2041%20%5Cdegree%7D%7D%7D%7D)
![▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪](https://tex.z-dn.net/?f=%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%20%20%7B%5Chuge%5Cmathfrak%7BAnswer%7D%7D%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA)
Let the numbers be x and y,
now, according to question :
by adding both equations we get,
now, let's plug the value of x in first equation to evaluate the value of y :
therefore, the required numbers are :