Answer:
<h2>A. 60 in³</h2>
Step-by-step explanation:
The formula of a volume of a cone:

r - radius
H - height
We have r = 1.9 in and H = 15 in. Substitute:


Adding all of the areas together:
5 x 6 = 30
4 x 6 = 24
3 x 6 = 18
4^2 + 3^2 = 16 + 9 = 25(square root) = 5
" " = 5
30 + 24 + 18 + 5 + 5 = 82 ft^2
Explanation
to solve this we need to translate into math terms, so
Step 1
a) let d represents the number of dimes
let n represents the number of nickles
so
re write the expressions

The number of nickels is three more than seven times the number of dimes in other words you have to add 7 to seven times the number of dimes to obtain the number of nickles
hence

therefore , the expression for the number of nickles is

I hope this helps you
The equation has to (or be transformed to) contain one object in the left side and the other object at the right side multiplied by a constant, without an independent term.
Answer:

Step-by-step explanation:
Given
See attachment for circles
Required
Ratio of the outer sector to inner sector
The area of a sector is:
For the inner circle

The sector of the inner circle has the following area

For the whole circle

The sector of the outer sector has the following area

So, the ratio of the outer sector to the inner sector is:


Cancel out common factor

Express as fraction
