All categories

2 years ago

HELP PLEASE HELP ME FIND THE AREA!!

Mathematics

2 answers:

nikklg [1K]2 years ago

6 0

Answer:63.75 ez

Step-by-step explanation:

first you multiply 10 x 8.5 and then divide by 2=85, after that you you divide by 2 =42.5 and you see the little triangle thats 42.5/2 wich is equal to 21.25 so after all of that you add 42.5+21.25 and you get the answer

andriy [413]2 years ago

5 0

Answer:

Not completely sure but I am pretty sure it is 850.

You might be interested in

A box with a square base and open top must have a volume of 97556 c m 3 cm3 . We wish to find the dimensions of the box that min

Kipish [7]

Answer:

S(x) = x² + 390224/x

Step-by-step explanation:

Volume of the open box = V = 97556 cm³

Material needed:

Let´s call x the side of the square base then the area of the base is

A(b) = x²

For the sides of the box, we have 4 sides each one with area of x*h

where h is the height of the box

The volume of the box V(b) = 97556 = x²*h then h = 97556/x²

S(x,h) = x² + 4*x*h*

The surface area of the box as function of x is:

S(x) = x² + 4*x*97556/x²

S(x) = x² + 390224/x

6 0

2 years ago

Solve for f.<br> –9 + 2f > – 3

kozerog [31]

F>3
That’s the answer

6 0

2 years ago

There is 4/6 of a pizza left from dinner . Each person gets 1/6 of a pizza for lunch the next day . How many people eat the pizz

kolezko [41]

Answer:

4 people eat the pizza for lunch

3 0

10 months ago

How do you find the derivative of 1/logx?

valentina_108 [34]

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

$With the chain rule. \\ 1log(x)=log(x)−1 \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\ \\−2⋅ddxlog(x) \\ =−1log(x)21x \\ =−1xlog(x)2 .$