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a_sh-v [17]
2 years ago
5

In a chemical reaction, which is the MOST LIKELY reactant for these products?

Chemistry
2 answers:
asambeis [7]2 years ago
8 0

Answer:

D

Explanation:

Nady [450]2 years ago
7 0
Only possible answer is D, because the reactants must contain the same atoms as the products. 
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Balance the equation, show steps:<br><br>Ag (s) + H2S (g) + O2 (g) ⟶ Ag2S (s) + H2O (l)
ehidna [41]
4Ag + 2H2S + O2 -> 2Ag2S + 2H20 i’m pretty sure that’s correct
5 0
2 years ago
Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptur
Scrat [10]

Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

Hank's Garage has an air compressor with a holding tank that contains a volume of 200L (V₁) of compressed air at a pressure of 5200 torr (P₁).

One day a hose ruptured and all the compressed air was released. The final pressure was the atmospheric pressure (1 atm = 760 torr) (P₂).

We can calculate the new volume (V₂) in these conditions using Boyle's law, which states there is an inverse relationship between the volume and the pressure of an ideal gas.

P_1 \times V_1 = P_2 \times V_2\\\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{5200 torr \times 200L}{760torr} = 1370 L

Hank's Garage has an air compressor with a holding tank that contains 200L of compressed air at 5200 torr. One day a hose ruptured and all the compressed air was released to a volume of 1370 L at atmospheric pressure.

Learn more: brainly.com/question/1437490

4 0
2 years ago
Barbiturates are synthetic drugs used as sedatives and hypnotics. Barbital ( = 184.2 g/mol) is one of the simplest of these drug
DanielleElmas [232]

Answer:

118.75°C is the boiling point of a solution.

Explanation:

Mass of the solute that is barbiturates = 42.5 g

Molar mass of a solute = 184.2 g/mol

Moles of solute = \frac{42.5 g}{184.2 g/mol}=0.2307 mol

Mass of the solvent that acetic acid = 825 g = 0.825 kg

molality=\frac{\text{Moles of solute}}{\text{Mass of solvent}}

Molality of the solution (m):

m=\frac{0.2307 mol}{0.825 kg}=0.2796 m

Elevation in boiling point is given as:

\Delta T_b=i\times K_b\times m

i = 1 (organic compound)

=1\times 3.07^oC/m\times 0.2796 m=0.8585^oC

\Delta T_b=T_b-T

T_b = Boiling temperature of solution.

T = boiling temperature of solvent that is acetic acid=117.9°C

0.8585^oC=T_b-117.9^oC

T_b=118.75 ^oC

118.75°C is the boiling point of a solution.

6 0
3 years ago
How do I write the formula for binary compounds
Ipatiy [6.2K]

Answer:

101010110101010101010101010101 ;)

Explanation:

3 0
3 years ago
A 22.4-L sample of which of the following substance, at STP, would contain 6.02 x 10^23 representative particles?
Veronika [31]
It would have to be carbon dioxide, the only gas listed. For gases, 1 mole of particles occupies 22.4 L of volume at STP.
6 0
3 years ago
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