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Andru [333]
3 years ago
6

If calcium has two valence electrons and fluorine has seven, how many fluorine atoms are needed to form an ionic bond with calci

um
Chemistry
2 answers:
Brut [27]3 years ago
8 0
There are 7 i just took the test
MaRussiya [10]3 years ago
5 0
Fluorine needs one electron to fill its orbital shell. It needs 8 valence electrons
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2. Which substance will form a solution with water? (Select all that app
cupoosta [38]

Answer:

sugar and salt, as they can dissolve in water. Sugar and salt have a high solubility in water. So, sugar and salt can form a solution with water.

Explanation:

7 0
2 years ago
Which compound contains both covalent and ionic bonds? <br> a. NCl3 b. NaF c. HCN d. NH4OH
Marina86 [1]
<h2>NH_4OH contains both covalent and ionic bonds.</h2>

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.

a. NCl_3 contain covalent bonds as they are made up of non metals only.

b. NaF contain ionic bonds as they are made up of sodium metal and fluorine non metal.

c. HCN contain covalent bonds as they are made up of non metals only.

d. NH_4OH contain  ionic bonds between NH_4 and OH and covalent between N and H in NH_4^+

Learn more about ionic and covalent bonds

brainly.com/question/13212100

brainly.com/question/2877158

8 0
2 years ago
How do water currents transfer heat different part of the ocean?
likoan [24]

Answer:

Energy in the ocean and the atmosphere

Explanation:

Hope this helps!

3 0
3 years ago
Calculate the pH of the solution that results when 20 mL of 0.2M HCOOH is mixed with 25mL of 0.2M NaOH solution.(post-equivalenc
Paul [167]

The pH of the solution : 12

<h3>Further explanation</h3>

Reaction

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

mol HCOOH =

\tt 20~ml\times 0.2~M=4~mlmol

mol NaOH =

\tt 25~ml\times 0.2~M=5~mlmol

Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]

ICE method :

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

4                          5

4                          4                     4                   4

0                          1                      1                    1

Concentration of [OH⁻] from NaOH :

\tt \dfrac{1~mlmol}{20+25~ml}=0.02

pOH=-log[OH⁻]

pOH=-log 10⁻²=2

pH+pOH=14

pH=14-2=12

3 0
3 years ago
Hurry please help I really need it
faust18 [17]

Answer:

CO2 & H2O

Explanation:

Anything on the right

6 0
2 years ago
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