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Andru [333]
4 years ago
6

If calcium has two valence electrons and fluorine has seven, how many fluorine atoms are needed to form an ionic bond with calci

um
Chemistry
2 answers:
Brut [27]4 years ago
8 0
There are 7 i just took the test
MaRussiya [10]4 years ago
5 0
Fluorine needs one electron to fill its orbital shell. It needs 8 valence electrons
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Which of the following is not a type of mechanical wave?
Otrada [13]
Concave is not a type of mechanical wave because it doesn’t need a medium for propagation.
3 0
3 years ago
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What does a nonpolar covalent bond show about the electronegativities of its
AleksandrR [38]

Answer:

B. The electronegativities of the two atoms are equal.

5 0
3 years ago
The equation below represents the combination of gaseous atoms of non-metal X and of hydrogen to form gaseous X2He6 molecules. 2
vichka [17]

Answer:

D +405.0kJ mol-¹

Explanation:

Since bond energy is the energy required to break a bond, the energy of dissociation of X₂H₆ = +2775 kJmol⁻¹.

Since there is one X-X bond and six X-H bonds,

Bond energy of one X-X bond + Bond energy of six X-H bonds = energy of dissociation of X₂H₆.

Since bond energy of one X-H bond = 395 kJ mol⁻¹, then

Bond energy of one X-X bond + Bond energy of six X-H bonds = energy of dissociation of X₂H₆

Bond energy of one X-X bond + 6 × one X-H bond = +2775 kJmol⁻¹.

Bond energy of one X-X bond + 6 × 395 kJ mol⁻¹ = +2775 kJmol⁻¹.

Bond energy of one X-X bond + 2370 kJ mol⁻¹ = 2775 kJmol⁻¹

Bond energy of one X-X bond = 2775 kJmol⁻¹ - 2370 kJ mol⁻¹

Bond energy of one X-X bond = +405 kJmol⁻¹

6 0
3 years ago
The pH scale for acids and bases ranges from _____.
Elza [17]
The pH scale for acids and bases ranges from 1 - 14. The answer is letter C. The rest of the choices do not answered the question above. There are quite a few relationships between [H+] and [OH−] ions. And because there is a large range of number between 10 to 10-15 M, the pH is used. pH = -log[H+] and pOH = -log[OH−]. In aqueous solutions, [H+ ][OH- ] = 10-14. From here we can derive the values of each concentration.

 

 -log[H+ ] + -log[OH- ] = -log[10-14]

pH + pOH = 14

So pH = 14 – pOH and pOH = 14 – pH 

8 0
3 years ago
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If a student has 50.0 mL of a solution of 0.100 M HCI, how could they make a solution with a concentration of 0.0500 M?
vfiekz [6]

Answer:

100 ml

Explanation:

c1×v1=c2×v2

50(0.100)=0.0500(v2)

5=0.0500(v2)

5/0.0500=0.0500/0.0500(v2)

100= v2

5 0
3 years ago
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