Answer:
A=5
Step-by-step explanation:
5-3a<-10 is the same as
5-3a=-10
So to solve it just solve for a.
subtract 5 from both sides
-3a=-15
dived -3 from both sides to get a alone
A=5
hope this helps!
The net change between the given values of the variable is 6a - 6
<h3>How to determine the net change between the given values of the variable?</h3>
The given parameters are
g(x) = 6x
Where
x = 1 and x =a
Calculate g(1) and g(a)
So, we have
g(1) = 6 * 1
g(1) = 6
g(a) = 6 * a
g(a) = 6a
The net change between the given values of the variable is
Change = g(a) - g(1)
So, we have
Change = 6a - 6
Hence, the net change between the given values of the variable is 6a - 6
Read more about functions at:
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Answer:
K still the same value
Step-by-step explanation:
given a reaction aA+bB<->cC+dD the constant K is defined as:
K is a constant so it won't change the value. Instead, the values of C and D are going to change. The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.
Answer:
90
Step-by-step explanation:
1/5x+4=1/3x-8
add 8 to both sides and subtract 1/5x from both sides
4+8=1/3x-1/5x
12=5/15x-3/15x
12=2/15x
divide both sides by 2/15
12÷2/15=x
when dividing by a fraction, invert and multiply
12*15/2=x
90=x
CHECK:
1/5(90)+4=1/3(90)-8
18+4=30-8
22=22
