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Svet_ta [14]
4 years ago
15

A distance is calculated from the equation d gt2. g is exactly known to be 9.8014 m/s and t is measured to be 2.4 0.2 s. What is

the distance and the uncertainty in the distance?
Physics
1 answer:
Yuri [45]4 years ago
8 0

Explanation:

The distance covered by an object is given by the following equation as :

d=\dfrac{1}{2}gt^2..............(1)

Where

g is the acceleration due to gravity

t is the time

The value of t is measured to be, t=(2.4\pm 0.2)\ s

To find the distance covered, put the value of t = 2.4 s in equation (1).

d=\dfrac{1}{2}\times 9.8\times (2.4)^2

d = 28.224 meters

To find the uncertainty in the distance, put the value of t = 0.2 s in equation (1) as :

d=\dfrac{1}{2}gt^2

d=\dfrac{1}{2}\times 9.8\times (0.2)^2

d = 0.196 meters

Hence, this is the required solution.

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Answer: hello  below is the missing part of your question

A mass m = 10 kg rests on a frictionless table and accelerated by a spring with spring constant k = 5029 N/m. The floor is frictionless except for a rough patch. For this rough path, the coefficient of friction is μk = 0.49. The mass leaves the spring at a speed v = 3.4 m/s.

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x = 0.0962 m

Explanation:

<em>First step :</em>

Determine the length of the rough patch/spot

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<em>next : </em>

work done on unstretched spring length

Given that block travels halfway i.e. d = 0.9694 / 2 = 0.4847 m

w' = Uₓ (mg)  * d

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An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 24 cm and one convex surface of radi
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convex radius r2 = 19.1 cm

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solution

we will apply here lens formula to find focal length f

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put here all value

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