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Len [333]
3 years ago
13

I need help, thanks! :^)

Physics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

B. Air

Explanation:

I'm taking the exam rn ^^

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A wheel is rotating at a rate of 2.0 rev every 3.0s. through what angle, in radian , does the wheel rotate in 1.0s?​
igomit [66]

Answer:

4 \pi

Explanation:

First of all, let's convert 2.0 rev into radians:

1.0 rev = 2\pi rad\\2.0 rev = 4 \pi rad

This means that the angular speed of the wheel is

\omega = 2.0 rev/s = 4 \pi rad/s

The angle through which the wheel rotates in a time t is given by

\theta=\omega t

And substituting t=1.0 s, we find

\theta=(4\pi rad/s)(1.0 s)=4 \pi rad

7 0
3 years ago
A wave has angular velocity 12 rad/sec and maximum displacement X cm (X= last two digit [1] of your student’s ID). Calculate the
Naily [24]

Answer:

a=1440\ m/s^2

Explanation:

Given that,

The angular velocity of a wave, \omega=12\ rad/s

The maximum displacement of the wave, A = 10 cm (let)

The maximum acceleration of the wave is given by :

a=-A\omega^2

Put all the values,

a=10\times 12^2\\\\a=1440\ m/s^2

So, the maximum acceleration of the wave is equal to 1440\ m/s^2.

4 0
3 years ago
A car with a mass of 2.0×10^3 kg is traveling at 15m/s .what is the momentum of the car ?
Maurinko [17]
Hello,

<span>A car with a mass of 2.0×10^3 kg is traveling at 15m/s. We need to find the momentum of the car. To do so, follow this formula:

p=mv

Where,

p = momentum 
m = mass
v = </span>velocity

The cars mass is 2.0E3 and its velocity is 15m/s. Therefore:

p=2.0  x 10^3 *15 or 2000(15)

p=30000

Thus, the cars momentum is 30000 kg m/s

Faith xoxo
7 0
3 years ago
The plate is suspended using the three cables which exert the forces shown, express each force as a cartesian vector
Westkost [7]

solution:

write the coordinates of the points A and B  

A= (0,0,14)ft

B= (5,-6,0)ft

write the position vector of a with recpect to b

R_{BA}=(0-5)i+(0-(-6))j+(14-0)k

     =-5i+6k+14k

calculation of a magnitude of the vector R_{BA}

\left | R_{BA} \right |=\sqrt{(-5)^2+6^2+14^2}

                      =\sqrt{25+36+196}

                      =16.031ft

calculation of the unit vector  

\frac{-5i+6k+14k}{16.031}

calculation of the force

F_{BA}=R_{BA}U_{BA}  

here, F_{BA} is the magnitude of the force.

substitute 350lb for F_{BA} and (\frac{-5i+6k+14k}{16.031}) for U_{BA}.

F_{BA} = 350 x (\frac{-5i+6k+14k}{16.031})

      =-109.2i+131j+305.7k lb

6 0
3 years ago
A temperature unit is known as a _____. <br> kilogram<br> calorie<br> joule <br> kelvin
svlad2 [7]
A temperature unit is known as a Kelvin
6 0
3 years ago
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