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3 years ago

What are some predicted affects of climate change linked to global warming

Physics

1 answer:

Alla [95]3 years ago

5 0

Decrease in atmospheric ozone, which results in lower protection from various stellar particles

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Material A is less optically dense than material B. How can you tell from the diagram above?

zimovet [89]

You can tell because the line bends and the closer it is to horizontal or past horizontal it is more dense

7 0

3 years ago

A child’s toy arrow is launched horizontally from a bow at a speed of 8 m/s from a second story window 4 meters above the ground

Westkost [7]

First find the time it takes to hit the sand t
using s=1/2 g t^2
t^2= 8/9.8= 0.82 seconds
This means the sand was s = 8 * 0.82 = 6.5m away
The horizontal speed stays constant at 8 m/s
The vertical speed =.82 * 9.8 = 8.0 m/s
As the two velocities are equal the angle must be 45 degrees to the horizontal

7 0

3 years ago

According to Heisenberg's uncertainty principle, the more we know about a particle's momentum, the less we know about its ______

Hoochie [10]

Answer:

location.

Explanation:

Heisenberg uncertainty principle states that it is basically impossible to know the exact position and momentum of a particle at the same time. According to my research on this principle, I can say that based on the information provided within the question the more we know of the momentum the less we know about it's location.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

7 0

3 years ago

A block of mass 0.252 kg is placed on top of a light, vertical spring of force constant 4 825 N/m and pushed downward so that th

svp [43]

Answer:

10.77m

Explanation:

The elastic potential energy of the spring when compressed with the mass is converted to the kinetic energy of the mass when released. This ie expressed in the following equation;

$\frac{1}{2}ke^2=\frac{1}{2}mu^2..............(1)$

where k is the force constant of the spring, e is the compressed length, m is the mass of the block and u is the velocity with which the block leaves the spring after being released.

If we make u the subject of formula from equation (1) we obtain the following;

$u=\sqrt{\frac{ke^2}{m}}................(2)$

Given;

e = 0.105m,

k = 4825N/m,

m = 0.252kg,

u = ?

Substituting all values into equation (2) we obtain the following;

$u=\sqrt{\frac{4825*0.105^2}{0.252}}................(2)\\u=14.53m/s$

The maximum height attained is then obtained from the third equation of motion as follows, taking g as $9.8m/s^2$

$v^2=u^2-2gh.........(3)$

v = 0m/s

Hence

$h=\frac{u^2}{2g}\\h=\frac{14.53^2}{2*9.8}\\h= 10.77m$

7 0

3 years ago

Calculate the efficiency of the following appliances:

lubasha [3.4K]

Answer:

1. The efficiency of the radiator is 90 %

2. The efficiency of the torch is 65 %

3. The efficiency of the car is 40 %

4. The efficiency of the energy saver is 70 %

5. The efficiency of the speaker is 50 %

Explanation:

Efficiency = (Useful energy out ÷ Total energy in) × 100 J

1. Useful energy = 900 J

The total energy in = 1000 J

The efficiency of the radiator = ((900 J)/(1,000 J)) × 100 % = 90 %

2. Useful energy = 65 J

The total energy in = 100 J

The efficiency of the torch = ((65 J)/(100 J)) × 100 % = 65 %

3. Useful energy = 4,000 J

The total energy in = 10,000 J

The efficiency of the car = ((4,000 J)/(10,000 J)) × 100 % = 40 %

4. Useful energy = 700 J

The total energy in = 1,000 J

The efficiency of the energy saver = ((700 J)/(1,000 J)) × 100 % = 70 %

5. Useful energy = 50 J

The total energy in = 100 J

The efficiency of the speaker = ((50 J)/(100 J)) × 100 % = 50 %

4 0

3 years ago