Answer:
18
Step-by-step explanation:
252 is a composite number. The exponents in the prime factorization are 2, 2, and 1. Adding one to each and multiplying we get (2 + 1)(2 + 1)(1 + 1) = 3 x 3 x 2 = 18. Therefore 252 has 18 factors.
Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Side AB and side AD are perpendicular because they cross at a ninety degree angle, and the sides are also the same length.
Answer:
y=0
Step-by-step explanation:
Find where the expression
10
x
is undefined.
x
=
0
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
where
n
is the degree of the numerator and
m
is the degree of the denominator.
1. If
n
<
m
, then the x-axis,
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
.
3. If
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
and
m
.
n
=
0
m
=
1
Since
n
<
m
, the x-axis,
y
=
0
, is the horizontal asymptote.
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
0
Horizontal Asymptotes:
y
=
0
No Oblique Asymptotes
image of graph
First one: x would be equal to 8 because the angles opposite sides 8 and x are congruent (isosceles triangle)
Second one: x is 75° because the sides opposite x and 75° are congruent (isosceles triangle)
Third one: This is an equilateral triangle since all the sides are equal. In equilateral triangles, every angle is 60° because 60*3=180. So both x and y are 60°
Fourth one: We know that all three angles in a triangle add to 180°. And we also know that the last unlabled angle would be equal to x because this is an isosceles triangle. So we can write
x+x+38=180 (combine like terms)
2x+38=180 (subtract 38 from both sides)
2x=142 (divide both sides by 2)
x=71°
Fifth one: This is an equilateral triangle so all the angles are congruent and add to 180. So we can write
3(4x+12)=180 (distribute)
12x+36=180 (subtract 36 from both sides)
12x=144 (divide both sides by 12)
x=12
Last one: Since the two given angles are opposite congruent sides, these angles are equal. Therefore, we can just make each of these angles 3x to solve for x first. And since we know the last angle is 90° we can write
3x+3x+90=180 (combine like terms)
6x+90=180 (subtract 90 from both sides)
6x=90 (divide both sides by 6)
x=15
So the angle 3x would be 3*15 or 45.
So we can set 45 equal to y+7 and solve for y
y+7=45 (subtract 7 from both sides)
y=38
Hope this helps<span />