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stealth61 [152]
3 years ago
13

What is true about side AB and side AD?

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0
Side AB and side AD are perpendicular because they cross at a ninety degree angle, and the sides are also the same length. 
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Jon has to choose which variable to solve for in order to be able to do the problem below in the most efficient manner.
yuradex [85]

The most efficient way to solve this problem is isolating the y in the first equation because:

6x + 3y = 27

3y = 27 - 6x

y = 9 - 2x

Since all the numbers have a common factor of 3, it can be easily simplified/reduce.

If you used any other variable, you would have gotten a fraction.

Now that you found y, you can substitute it into the other equation to solve for x.  

ANYWAYS, your answer is A

7 0
4 years ago
Read 2 more answers
In a square PQRS, PQ = 2x +3 cm and QR = 3x – 5 cm, then the value of x is
Eva8 [605]

Answer:

x = 8 cm

Step-by-step explanation:

Given that,

In a square PQRS, PQ = 2x +3 cm and QR = 3x – 5 cm.

We need to find the value of x.

In a square, all the sides are equal. So,

PQ = QR

2x +3 = 3x – 5

3+5 = 3x - 2x

x = 8

So, the value of x is equal to 8 cm.

6 0
3 years ago
I’ve been stuck on these for a while, can someone help? Thank you :) !!
natulia [17]

Answer:

6.32

5

254.34

Step-by-step explanation:

The lengths of the missing sides can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

first missing side

7² = 3² + x²

49 = 9 + x²

x² = 49 - 9

x² = 40

x = 6.32

second missing side

3² + 4²

9 + 16

= 25

√25 = 5

Area of a circle = πr²

Where : = π = pi = 3.14

3.14 x 9² = 254.34

6 0
3 years ago
How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At
ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

                              =s=3 \times 10^8 \frac{\text{meter}}{\text{second}}

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

    That is Speed of light in another medium

                 =w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

  \rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}

             

7 0
4 years ago
Read 2 more answers
Alexis has a cylindrical trash can with a diameter of 24 cm and a height of 42 cm. What is the approximate volume of the trash c
Alisiya [41]

Answer:

C

Step-by-step explanation:

3 0
4 years ago
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