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Marianna [84]
3 years ago
11

Solve for ddd. Give an exact answer. 0.5(7d+4)=7-1.5d0.5(7d+4)=7−1.5d0, point, 5, left parenthesis, 7, d, plus, 4, right parenth

esis, equals, 7, minus, 1, point, 5, d=
Mathematics
1 answer:
MissTica3 years ago
4 0

Answer:

d = 1

Step-by-step explanation:

The equation given is:

0.5(7d + 4) = 7 - 1.5d

Expand the bracket:

3.5d + 2 = 7 - 1.5d

Collect like terms:

3.5d + 1.5d = 7 - 2

5d = 5

d = 5 / 5 = 1

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(8.6x107)-(9.1x10-8)simplify
natima [27]

Answer:

  85,999,999.999 999 909

Step-by-step explanation:

The expression represents the difference of a relatively large number and one that is relatively small. That difference is approximately the value of the large number. The exact value requires 17 digits for its proper expression. Most calculators and spreadsheets cannot display this many digits.

<h3>Standard form</h3>

The numbers in standard form are ...

  86,000,000 = 8.6×10^7

  0.000000091 = 9.1×10^-8

<h3>Difference</h3>

Their difference is ...

  86,000,000 -0.000000091 = 85,999,999.999 999 909

In scientific notation, this is ...

  8.599 999 999 999 990 9×10^7

4 0
2 years ago
X + (4 1/3)= (-2 5/6)
vladimir1956 [14]

Answer:

x+((4 + 1/3))=(-(2 + 5/6))

6x = -43  

x≈ -7.166667


3 0
3 years ago
I need help with this please
oksano4ka [1.4K]

Answer:i can's see it very well sorry kid

12

Step-by-step explanation:i dont know

5 0
3 years ago
[1x-6]&gt;1 what are the solutions
a_sh-v [17]

Answer:

x > 7

(I think this is Right but not sure yet )

3 0
3 years ago
(4/2)4 + (1 + 3)?<br><br> I really need help!
Katyanochek1 [597]

\huge\text{Hey there!}

\large\text{Just do PEMDAS}

\large\text{Parentheses}

\large\text{Exponents}

\large\text{Multiplication}

\large\text{Division}

\large\text{Addition}

\large\text{Subtraction}

\mathsf{(\dfrac{4}{2})(4) + (1+3)}

\mathsf{\dfrac{4}{2} = 2}

\mathsf{2(4) + (1 + 3)}

\mathsf{2(4) = 8}

\mathsf{8 + (1 + 3)}

\mathsf{1 + 3 = 4}

\mathsf{8 + 4 = 12}

\boxed{\boxed{\large\text{Answer: \bf \huge12 }}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day! }

~\frak{Amphitrite1040:)}

6 0
3 years ago
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