Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Answer: x = 8
Step-by-step explanation:
Hello again XD.
This is a coordinate plane and all the angles on a coordinate plane add up to 360°
Divide 360 by 4 to get the measurement of the section we are working in.
360/4 = 90°
This means it is complementary and complementary angles state that both separate angles added together = 90°
therefore,
6x + 2 + 40 = 90
combine like terms:
6x + 42 = 90
now subtract 42 from both sides
6x = 48
divide 6 from both sides to get:
x = 8
Let me know if you have any more questions you want answered and I hope I explained this well.
Answer:
14
Step-by-step explanation:
subtracting by 11 gets you 14
Greatest common factor is 1 for the first one and the second one is also 1
Answer:
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Step-by-step explanation:
