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masya89 [10]
3 years ago
14

Jane works 3 times as fast as Eleanor. If they work together they can do a job in 21 minutes. How long does it take Eleanor to d

o the job by herself?
Mathematics
2 answers:
erik [133]3 years ago
6 0

Answer:

Eleanor's work 1h 24'

Step-by-step explanation:

e-lub [12.9K]3 years ago
4 0

Answer:

1 hour and 24 min

Step-by-step explanation:

Jane does 3/4 job done in 21 min

Eleanor does 1/4 job done in 21 min

21*4=84

60+24

1 hour and 24 min

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Increase 120 centimetres by 24%
Eva8 [605]
It is a simple problem where 120 centimeters need to be increased by 24%. The increased length can be found by:
120 * (24/100)
= 12 * (24/10)
= 288/10
= 28.8 centimeters
Then the total length of increase = 28.8 cm
Then the increased length = (120 + 28.8) cm
                                         = 148.8 cm
So the length becomes 148.8 cm after it is increased by 24%.
3 0
4 years ago
Simplify this expression;<br>3(2x+7)
Advocard [28]

Answer:

6x+21 (Maybe)

Are you doing the buddy method, how is your teacher wanting to do this, When you respond I might have the correct answer

(buddy method) Multiply the 2x and 7 by the 3 giving you 6x+21 and then that's it you cant do anything else but I don't know if that's how you're teacher wants it done.


5 0
3 years ago
Read 2 more answers
Find the equation of perpendicular bisector of the lines with the given word (1,2) and (5,4) ​
Mandarinka [93]

Answer:

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Step-by-step explanation:

Slope: (4-2)/5-1) = 2/4 = 1/2

Slope of the perpendicular line: -2

y-intercept: 2 - (-2)(1) = 4

7 0
3 years ago
I don’t understand anything someone please help me :/
Artist 52 [7]

Answer:

answer choice c=6

Step-by-step explanation:

since the question says that round to the nearest

mile then you would round 5.7 to get you 6 so

your answer is 6

Hope this help you :))

 please give me branliest.                                                              

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3 years ago
Use the graph to determine the function's domain and range.
Nat2105 [25]
Dom (-∞,∞) Ran [-5,∞)
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3 years ago
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