Calculate the resulting ph obtained by mixing 16.5 g hcl and 22.6 g nacl in water to create 482 l solution.

Chemistry

1 answer:

mr Goodwill [35]3 years ago

3 0

<h3><u>Answer</u>;</h3>

pH = 3.03

<h3><u>Explanation</u>;</h3>

NaCl is a neutral salt and does not affect the pH.

moles HCl = g HCl / MM

= 16.5 / 36.5

= 0.452 equivalent to moles H+

Molarity H+ = moles H+ / L

= 0.452 / 482

= 0.000938 M

Hence; pH = -log[H+]

= -log(0.000938)

= 3.03

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