Question

If 4 dooms = 7 farzes, 1 bing = 2 wots, 2 zots = 3 dooms, and 9 farzes = 4 bings, then 3 zots = ? wots.

Answer 1

Answer : $3\text{ zots}=7\text{ wots}$

Explanation :

As we are given that:

4 dooms = 7 farzes

1 bing = 2 wots

2 zots = 3 dooms

9 farzes = 4 bings

Now we have to calculate 3 zots = ? wots.

We have to start from left hand side value (L.H.S).

$3\text{ zots}$

$2\text{ zots}=3\text{ dooms}$

$\text{ zots}=\frac{3}{2}\text{ dooms}$

$\Rightarrow 3\times \frac{3}{2}\text{ dooms}$

$4\text{ dooms}=7\text{ farzes}$

$\text{ dooms}=\frac{7}{4}\text{ farzes}$

$\Rightarrow 3\times \frac{3}{2}\times \frac{7}{4}\text{ farzes}$

$9\text{ farzes}=4\text{ bings}$

$\text{ farzes}=\frac{4}{9}\text{ bings}$

$\Rightarrow 3\times \frac{3}{2}\times \frac{7}{4}\times \frac{4}{9}\text{ bing}$

$1\text{ bings}=2\text{ wots}$

$\text{ bings}=\frac{2}{1}\text{ wots}$

$\Rightarrow 3\times \frac{3}{2}\times \frac{7}{4}\times \frac{4}{9}\times \frac{2}{1}\text{ wots}$

$\Rightarrow 7\text{ wots}$

Thus, $3\text{ zots}=7\text{ wots}$

Answer 2

3 zots = 7 wots

3 zots × (3 dooms/2 zots) = ⁹/₂ dooms

⁹/₂ dooms × (7 farzes/4 dooms) = ⁶³/₈ farzes

⁶³/₈  farzes × (4 bings/9 farzes) = ⁷/₂ bings

⁷/₂ bings × (2 wots/1 bing) = 7 wots