Answer: 
for the reaction 
is -108kJ
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
![\Delta H=[n\times B.E_{reactants}]-[n\times B.E{products}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bn%5Ctimes%20B.E_%7Breactants%7D%5D-%5Bn%5Ctimes%20B.E%7Bproducts%7D%5D)
where, n = number of moles
Now put all the given values in this expression, we get
![\Delta H=[1\times B.E_{Cl_2}+1\times B.E_{F_2}]-[2\times B.E_{ClF}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B1%5Ctimes%20B.E_%7BCl_2%7D%2B1%5Ctimes%20B.E_%7BF_2%7D%5D-%5B2%5Ctimes%20B.E_%7BClF%7D%5D)
![\Delta H=[(1\times 243)+(1\times 159)]-[2\times 255]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%281%5Ctimes%20243%29%2B%281%5Ctimes%20159%29%5D-%5B2%5Ctimes%20255%5D)
Thus for the reaction is -108kJ
Chemical reaction (dissociation) 1: C₂O₄H₂(aq) ⇄ C₂O₄H⁻(aq) + H⁺(aq).
Chemical reaction (dissociation) 2: C₂O₄H⁻(aq) ⇄ C₂O₄²⁻(aq) + H⁺(aq).
c(C₂O₄H⁻) = c(H⁺) = x.
c(C₂O₄H₂) = 0.0269 M.
pKa₁ = 1.23.
Ka₁ = 10∧(-1.23) = 0.059.
Ka₁ = c(C₂O₄H⁻) · c(H⁺) / c(C₂O₄H₂).
0.059 = x² / (0.0269 M - x).
Solve quadratic eqaution: x = c(H⁺) = 0.02 M.
pH = -log(0.02 M) = 1.7.
Answer:
first number is the correct answer
C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O
Shifting plates, underwater volcanoes. many different variables come in play
