Answer:
2,341g of CuSO₄.5H₂O
Explanation:
It is possible to assume all loses water comes from CuSO₄.5H₂O. Thus:
0,8445g H₂O (1mol H₂O / 18,015g) = 0,04688 moles of water.
As 1 mole of contains 5 moles of water, moles of CuSO₄.5H₂O are:
0,04688 moles H₂O × (1 mole CuSO₄.5H₂O / 5 moles H₂O) = 9,38x10⁻³ moles of CuSO₄.5H₂O
The molecular mass of CuSO₄.5H₂O is 249,69g/mol. Thus, mass of 9,38x10⁻³ moles of CuSO₄.5H₂O is:
9,38x10⁻³ moles of CuSO₄.5H₂O × (249,69g / mol) =
<em>2,341g of CuSO₄.5H₂O </em>is the maximum quantity of CuSO₄.5H₂O that could be in the sample.
I hope it helps!
The volume of a solid is measured in cubic units i.e. cubic centimeter, cubic meter, cubic feet etc.
Answer:
Mercury
Chemical element
Symbol: Hg
Explanation:
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<span>Answer: 8.15s
</span><span />
<span>Explanation:
</span><span />
<span>1) A first order reaction is that whose rate is proportional to the concenration of the reactant:
</span><span />
<span>r = k [N]
</span><span />
<span>r = - d[N]/dt =
</span><span />
<span>=> -d[N]/dt = k [N]
</span><span />
<span>2) When you integrate you get:
</span><span />
<span>N - No = - kt
</span>
<span></span><span /><span>
3) Half life => N = No / 2, t = t'
</span><span />
<span>=> No - No/ 2 = kt' => No /2 = kt' => t' = (No/2) / k
</span><span />
<span>3) Plug in the data given: No = 0.884M, and k = 5.42x10⁻²M/s
</span>
<span /><span /><span>
t' = (0.884M/2) / (5.42x10⁻²M/s) = 8.15s</span>
5.5 grams of reactants. According to the Law of Conservation of Mass, mass isn’t created or lost through any chemical changes, so the total mass should remain constant from the initial reactants to the final products.
