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11Alexandr11 [23.1K]

3 years ago

12

Each glucose molecule consists only of carbon, hydrogen, and oxygen atoms. If each molecule contains 53.3% oxygen and 6.7% hydro

gen by mass, what percentage of each glucose molecule is made up of carbon

1 answer:

andrew11 [14]3 years ago

6 0

Percentage = 100 - 53.3% - 6.7%
Percentage = 40%

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Answer:

$3.65~M$

Explanation:

We have to remember the <u>molarity equation</u>:

$M=\frac{mol}{L}$

So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the <u>conversion</u>:

$100~mL\frac{1~L}{1000~mL}=~0.1~L$

Now we can calculate the moles. For this we have to calculate the <u>molar mass</u>:

O: 16 g/mol

H: 1 g/mol

C: 12 g/mol

$(16*1)+(1*4)+(12*1)=32~g/mol$

With the molar mass value we can <u>calculate the number of moles</u>:

$1.7~g~of~CH_3OH\frac{1~mol~CH_3OH}{32~g~of~CH_3OH}=0.365~mol~CH_3OH$

Finally, we can <u>calculate the molarity</u>:

$M=\frac{0.365~mol~CH_3OH}{0.1~L}=3.65~M$

I hope it helps!

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shutvik [7]

Answer:

look at the picture

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2 years ago

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The percent of histidine side chains would be deprotonated at pH 7.5 is 5.77 %.

<h3>What is pKa?</h3>

The term pKa refers to the negative logarithm of the acid dissociation constant (Ka). The pH is the negative logarithm of the hydrogen ion concentration.

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Learn more about percent dissociation: brainly.com/question/12273293

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