Answer:
The answer is True
Explanation:
I got it right on my quiz, hope this helps!
Answer:
11.9 is the pOH of a 0.150 M solution of potassium nitrite.
Explanation:
Solution : Given,
Concentration (c) = 0.150 M
Acid dissociation constant =
The equilibrium reaction for dissociation of (weak acid) is,
initially conc. c 0 0
At eqm.
First we have to calculate the concentration of value of dissociation constant .
Formula used :
Now put all the given values in this formula ,we get the value of dissociation constant .
By solving the terms, we get
No we have to calculate the concentration of hydronium ion or hydrogen ion.
Now we have to calculate the pH.
pH + pOH = 14
pOH =14 -2.1 = 11.9
Therefore, the pOH of the solution is 11.9
Answer:
The u (amu is the old unit name) is 1/12 of the weight of an 12C atom. The way the u is chosen ensures that all core and atom masses are multiples of 1(±0.1) u.
Explanation:
Further explanation if needed...
Carbon 12 was chosen because the chemical atomic weights based on C12 are almost identical to the chemical atomic weights based on the natural mix of oxygen. Simply because the atomic mass is defined as 1/12 of the mass of 12C. Others isotopes of carbon (13C mostly, with an abundance of 1.1% approximately) account for an average atomic mass slightly above 12.
First we have to refer
to the reaction between the acid and the base: <span>
H2SO4 + 2 NaHCO3 ---> 2 H2O + 2 CO2 + Na2SO4
From this balanced equation we can see that for every 1 mol
of acid (H2SO4), we need 2 mol of base (NaHCO3) to neutralize it. Given 28 ml
of 5.8 M acid, we need to find out how many mols of acid that is:
<span>28mL * (1L/1000mL) * 5.8 mol/L = 0.1624 mol H2SO4</span></span>
<span>
Since we need 2 mol of base per mol of acid, we need:</span>
<span> 2*0.1624 mol = 0.3248 mol NaHCO3 </span><span>
MolarMass of NaHCO3 is 84.01 g/mol
<span>0.3248 mol*(84.01g/mol) = 27.29 g NaHCO3</span></span>
Answer:
If you have ever been in a room when a piping hot pizza was delivered, you have been made aware of the fact that gaseous molecules can quickly spread throughout a room, as evidenced by the pleasant aroma that soon reaches your nose. Although gaseous molecules travel at tremendous speeds (hundreds of meters per second), they collide with other gaseous molecules and travel in many different directions before reaching the desired target.
Explanation:
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