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Mila [183]
3 years ago
13

Every time kelly eats 3 cookies, Diego can finish 4 cookies. When are they going to eat the same number of cookies?

Mathematics
1 answer:
maw [93]3 years ago
8 0

Answer:

In about 4 hours I think

Step-by-step explanation:

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PLEASE HELP I'M TIMED
DedPeter [7]

Really hope i'm right

1st row

the first one is length less than 10

one next to it is width greater than 5

next to that is length greater than 10

2nd row

the first one is length greater than 10

one next to that is width less than 5

next to that is width greater than 5

3rd row

first one is width less than 5

and last is length less than 10

4 0
3 years ago
The Green Line circles the station every 9 minutes. The red live circles the station every 6 minutes. If they leave the station
maria [59]
D) Because if you do 9 *6 you get 54 minutes until the next time.



4 0
3 years ago
Is this all correct?
expeople1 [14]
Yes it looks like it would be right
3 0
3 years ago
Read 2 more answers
Solve for the given variable. Record your work and check the solution, if possible.
nikdorinn [45]

Answer:

10

Step-by-step explanation:

75c-300=25c+200

-25c         -25c

50c-300=200

+300         +300

50c=500

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4 0
2 years ago
Read 2 more answers
Stacy uses a spinner with six equal sections numbered 2, 2, 3, 4, 5, and 6 to play a game. Write a probability model for this ex
allsm [11]

Answer:

We estimate to have 8.33 times the number 6 in 50 trials.

Step-by-step explanation:

Let us consider a success to get a 6. In this case, note that the probability of having a 6 in one spin is 1/6. We can consider the number of 6's in 50 spins to be a binomial random variable. Then, let X to be the number of trials we get a 6 out of 50 trials. Then, we have the following model.

P(X=k) = \binom{50}{k}(\frac{1}{6})^k(\frac{5}{6})^{50-k}

We will estimate the number of times that she spins a 6 as the expected value of this random variable.

Recall that if we have X as a binomial random variable of n trials with a probability of success of p, then it's expected value is np.

Then , in this case, with n=50 and p=1/6 we expect to have \frac{50}{6} number of times of having a 6, which is 8.33.

6 0
3 years ago
Read 2 more answers
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