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3 years ago

Which statement best describes the interquartile range of this set of weights?

Mathematics

1 answer:

Alex Ar [27]3 years ago

6 0

Answer:

Step-by-step explanation:

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Nancy’s nut store sells peanuts for $2 per pound and cashews for $10 per pound. The store sells a peanut - cashew mixture for $7

Gelneren [198K]

9514 1404 393

Answer:

25 pounds cashews
15 pounds peanuts

Step-by-step explanation:

Let c represent the number of pounds of cashews in the mix. Then 40-c is the number of pounds of peanuts. The total cost of the mix is ...

10c +2(40 -c) = 7(40)

8c +80 = 280 . . . . simplify

c +10 = 35 . . . . . . . divide by 8

c = 25 . . . . . . . . . . subtract 10

40-c = 40-25 = 15 . . . . pounds of peanuts

25 pounds of cashews and 15 pounds of peanuts should be used in the mix.

5 0

2 years ago

Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)

astraxan [27]

Answer: $4\sqrt{3}$ .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

$D=\sqrt{(d-b)^2+(b-a)^2}$

Distance between points $(-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})$ .

$D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}$

Hence, the correct option is $4\sqrt{3}$ .

3 0

3 years ago

Please help ASAP 10 points

dimulka [17.4K]

Answer:-4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Least common denominator?

Over [174]

Answer:

$\large\boxed{(s-2)(s+2)(s-3)=(s^2-4)(s-3)=s^3-3s^2-4s+12}$

Step-by-step explanation:

$s^2-4=s^2-2^2=(s-2)(s+2)\\\\\text{used}\ a^2-b^2=(a-b)(a+b)\\\\s^2-5s+6=s^2-2s-3s+6=s(s-2)-3(s-2)=(s-2)(s-3)\\\\\text{Therefore}\ LCD(s^2-4,\ s^2-5s+6)=(s-2)(s+2)(s-3)$

4 0

3 years ago

Raj gets a 1.5 mile head start and runs at a rate of 4.5 miles per hour. Jacinda's progress is represented by a graph that goes

Alexxandr [17]

From the given ordered pair representing Jacinda's progress, her speed is equal to 10 miles per hour. Letting x be the time it takes for Jacinda to catch up with Raj, the total distance Raj would travel is
1.5 + 4.5x
and Jacinda's total distance is 10x. Mathematically,
1.5 + 4.5x = 10x
The value of x from the equation is 0.27 hours. Therefore, Jacinda needs to run 2.7 miles to catch up with Raj.

6 0

3 years ago