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Juli2301 [7.4K]
2 years ago
15

Anne picked out 3 board games from her cabinet to take to a game night with her friends. She still has more than 10 board games

in the cabinet, so she thinks she could bring a few more. Let x represent how many board games were in Anne’s cabinet to start. Which inequality describes the problem?

Mathematics
1 answer:
Tresset [83]2 years ago
8 0

Answer:

x - 3 > 10

There were more than

13

board games in Anne's cabinet to start.

Step-by-step explanation:

The variable x represents how many board games were in Anne's cabinet to start. Since she has already picked out 3 board games to bring, the expression x–3 represents how many board games are still in the cabinet.

And, since Anne has more than 10 board games still in her cabinet, x–3 must be greater than 10.

This inequality shows the relationship.

x–3>10

Now, solve for x.

x–3

> 10

x–3+3

> 10+3 Add 3 to both sides

x

> 13 Simplify

So, there were more than 13 board games in Anne's cabinet to start.

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The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
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Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

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We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

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40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

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Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

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Therefore, 4500 end-zone tickets were sold.

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