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puteri [66]
4 years ago
5

if a question is testable and can provide an answer based on empirical observations and reasonable logic, it can be answered wit

h science. true or false?
Chemistry
2 answers:
ArbitrLikvidat [17]4 years ago
8 0

Answer:

true

Explanation:

statuscvo [17]4 years ago
4 0

Answer:

true

Explanation:

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She collected 20 cm³ of oxygen. What volume of hydrogen could she also have collected at the same time?
loris [4]

Answer:

Assuming it was collected from the atmosphere it would be virtually nothing

Explanation:

hydrogen makes up 0.000055% of the atmosphere while oxygen makes up 23 percent. 20/400000 cm^3 of hydrogen

7 0
3 years ago
What is the equation for synthesis
lawyer [7]
A synthesis reaction can be represented by the general equation: A + B → C. In this equation, the letters A and B represent the reactants that begin the reaction, and the letter C represents the product that is synthesized in the reaction.
5 0
3 years ago
Calculate the amount of heat required to convert 10.0 grams of ice at –20.°C to steam at 120.°C. (Sp. heat of H2O(s) = 2.09 J/g•
allsm [11]

Answer : The amount of heat required is, 3.09\times 10^4J

Solution :

The process involved in this problem are :

(1):H_2O(s)(-20^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(120^oC)

The expression used will be:

\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+m\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]

where,

\Delta H = heat required for the reaction

m = mass of ice = 10.0 g

c_{p,s} = specific heat of solid water or ice = 2.09J/g^oC

c_{p,l} = specific heat of liquid water = 4.18J/g^oC

c_{p,g} = specific heat of gaseous water = 2.03J/g^oC

\Delta H_{fusion} = enthalpy change for fusion = 333J/g

\Delta H_{vap} = enthalpy change for vaporization = 2260J/g

Now put all the given values in the above expression, we get:

\Delta H=[10.0g\times 2.09J/g^oC\times (0-(-20))^oC]+10.0g\times 333J/g+[10.0g\times 4.18J/g^oC\times (100-0)^oC]+10.0g\times 2260J/g+[10.0g\times 2.03J/g^oC\times (120-100)^oC]

\Delta H=30934J=3.09\times 10^4J

Therefore, the amount of heat required is, 3.09\times 10^4J

7 0
4 years ago
Mercury is often released into water bodies with industrial effluents, where it is then converted to the compound form methylmer
sergeinik [125]
 This is more to do with Bioaccumulation of mercury, where the mercury is absorbed into the issue of animals, and so animals higher in the food chain consume a lot of tissue matter hence increasing mercury content in their system.
7 0
3 years ago
What temperature air has low pressure?
finlep [7]

Explanation:

A low-pressure area, or "low", is a region where the atmospheric pressure at sea level is below that of surrounding locations. Low-pressure systems form under areas of wind divergence that occur in upper levels of the troposphere.

5 0
3 years ago
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