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3 years ago

She collected 20 cm³ of oxygen. What volume of hydrogen could she also have collected at the same time?

Chemistry

1 answer:

loris [4]3 years ago

7 0

Answer:

Assuming it was collected from the atmosphere it would be virtually nothing

Explanation:

hydrogen makes up 0.000055% of the atmosphere while oxygen makes up 23 percent. 20/400000 cm^3 of hydrogen

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20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc

bezimeni [28]

Answer:

Concentration of the barium ions = $[Ba^{2+}] = 0.4654 M$

Concentration of the chloride ions = $[Cl^{-}]=0.9308 M$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride = 0.1355 M

$n=0.1355 M\times 0.04389 L=0.005947 mol$

$Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O$

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

$\frac{1}{2}\times 0.05947 mol=0.029735 mol$ barium hydroxide

Moles of barium hydroxide = 0.029735 mol

$Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)$

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

$=1\times 0.029735 mol= 0.029735 mol$

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL = 63.89 mL = 0.06389 L

Concentration of the barium ions = $[Ba^{2+}]$

$[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M$

$Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)$

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

$[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M$

8 0

3 years ago

Can someone do these? Brainliest included

mixas84 [53]

Answer:

Explanation:

6. p⁺ e⁻

Ca²⁺ 20 18

F⁻ 9 10

O²⁻ 8 10

Na⁺ 11 10

7. Physical properties of matter are properties that can be measured or observed without matter changing to an entirely different substance. These include odor, boiling point, melting point, density, electrical conductivity and heat conductivity.

Separation of mixture:

Chromatography involves solvent separation on a solid medium.

Distillation takes advantage of differences in boiling points.

Evaporation removes a liquid from a solution to leave a solid material.

Filtration separates solids of different sizes.

Funnel partitioning with solvents. Solvent dissolves one component but not the other.

8.Bulk Elements => Carbon, Hydrogen, Oxygen, Nitrogen, Sulfur & Phosphouous

Microminerals are those minerals needed in less than 100 mg quantities. Trace minerals or trace elements are usually needed in microgram quantities. Microminerals include iron, zinc, copper, iodine, fluoride, chromium, cobalt, selenium, manganese, and molybdenum.

Diatomic Molecules => H₂, N₂, O₂, F₂, Cl₂, Br₂, I₂

9. Electron Configurations

Na: 1s²2s²2p⁶3s¹ => valence = 3s¹

N: 1s²2s²2p³ => valence = 2s²2p³

Al: 1s²2s²2p⁶3s²3p¹ => valence = 3s²3p¹

Valence is the highest principle quantum number (or, principle energy level ~ ring) in the electron configurations.

10.moles of glucose = 450g/180.16 g/mol =2.50 moles

C₂H₆O₂ = 2(12) + 6(1) + 2(16) = 24 + 6 + 32 = 62 g/mole

7 0

2 years ago

it takes 463 kJ/mol to break an oxygen-hydrogen single bond. calculate the maximum wavelength of light for which an oxygen-hydro

Marianna [84]

Answer:

2.59 × 10⁻⁷ m = 259 nm

Explanation:

You need to calculate the wavelength of a photon with an energy equal to 463 kJ/mol, which is the energy to break an oxygen-hydrogen atom.

The energy of a photon and its wavelength are related by the Planck - Einstein equation:

E = hν,

Where:

E = energy of a photon,

h = Planck constant (6.626 × 10⁻³⁴ J . s) and

ν = frequency of the photon.

And:

ν = c / λ

Where:

c = speed of light (3.00 × 10⁸ m/s in vacuum)

λ = wavelength of the photon

Thus, you can derive:

E = h c / λ

Solve for λ:

λ = h c / E

Before substituting the values, convert the energy, 463 kJ/ mol, to J/bond

463 kJ/ mol × 1,000 J/kJ × 1 mol / 6.022 × 10 ²³ atom × 1 bond / atom

= 7.69×10²³ J / bond

Substitute the values and use the energy of one bond:

λ = 6.626 × 10⁻³⁴ J . s × 3.00 × 10⁸ m/s / 7.69×10²³ J = 2.59 × 10⁻⁷ m

The wavelength of light is usually shown in nanometers:

2.59 × 10⁻⁷ m × 10⁹ nm / m = 259 nm ← answer

6 0

3 years ago

4. Which class of matter is the least evenly

lys-0071 [83]

Answer:

Pure iron sulfide is homogeneous (uniform in appearance and properties), shows constant composition (a consistent ratio of iron to sulfur throughout any sample of it, large or small), consists of molecules all of one type, is no longer separable into two separate substances without another chemical reaction, and is .

Explanation:

Mixtures in two or more phases are heterogeneous mixtures. ... The exception would be solutions that contain another phase of matter. For example, you can make a homogeneous solution of sugar and water, but if there are crystals in the solution, it becomes a heterogeneous mixture.

8 0

3 years ago

a sample of ideal gas at room temperature occupies a volume of 12.0 L at a pressure of 392 torr. if the pressure changes to 1960

Setler79 [48]

852 x 40.0= 4260 x v2
v2= 8 L 

b) 852 x 40 = p2 x 69.0 
p2= 494 torr

3 0

3 years ago