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olga2289 [7]
3 years ago
7

Help me rn plz......​

Chemistry
2 answers:
mel-nik [20]3 years ago
8 0
Anwers is B hope it helps please give me brainlessly please thanks have a nice day
dimulka [17.4K]3 years ago
3 0

Answer:

Explanation:

B

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Empirical formula of a compound composed of 32.1 g potassium (k) and 6.57 g oxygen (o)?
tester [92]

The empirical formula is K₂O.

The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.

The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.

So, our job is to calculate the <em>molar ratio</em> of K to O.

Step 1. Calculate the <em>moles of each element </em>

Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K

Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0

Step 2. Calculate the <em>molar ratio of each elemen</em>t

Divide each number by the smallest number of moles and round off to an integer

K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1

Step 3: Write the <em>empirical formula </em>

EF = K₂O

5 0
3 years ago
How many 3-liter balloons could the 12-L helium tank pressurized to 160 atm fill? Keep in mind that an "exhausted" helium tank i
vaieri [72.5K]

Answer:

The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

P_1V_1=P_2V_2

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

V₂ = 1920L

As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L×\frac{1balloon}{3L} = <em>636 balloons</em>

<em></em>

I hope it helps!

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3 years ago
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The coefficient for the chemical formula 3CO2 is the 3.
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Answer for this question might be number 2
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2 years ago
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I NEED HELP, PLEASE AND THANK YOU! &lt;3
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