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nadya68 [22]
3 years ago
5

How do you write 7 a mixed number in the simplest form

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
7 0

What does this even mean?

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Which relation is a function? {(1, 2), (2,4), (−1, 2), (0,3)}
Georgia [21]

Answer:

The last one :{(5, 0), (0, 1), (5, 2), (4,4)}

Step-by-step explanation:


8 0
3 years ago
Please help me with this
Citrus2011 [14]

I don't know the answer because of how zoomed in it is. But, you could make a cordinate grid and plot all of the numbers. Then, you would connect all of the lines and you will see that one line is missing in the parallelogram. You finish off that line yourself and write down the cordanite that you needed to complete the parallelogram. You will lastly put U=answer (the cordanite you got from finishing off the parallelogram).

5 0
3 years ago
I really need help with this ASAP​
Alexandra [31]

Answer:

No. of boxes = 10

Oranges per box = 56

Total no. of oranges = 56*10=560

No. of bad oranges = 560/40= 14

(i) Probability of bad orange = 14/560 = 1/40

(ii) no of oranges expected to be bad = 14 ( found above)

Hope it helps.............. :)

7 0
3 years ago
Help me find the answer <br>Tan 0 and Cot O ​
vesna_86 [32]

Answer:

Step-by-step explanation:

we can say the angle is also +45° going in the clock wise direction.  so take Tan(45)= 1

Cot(45) = 1

b/c  Tan(45) = Sin(45) /Cos(45) = (\sqrt{2}/2) / (\sqrt{2}/2)   ofc that's just 1

b/c Cot(45) = Cos(45) / Sin(45) , which is the same as above 1

3 0
3 years ago
Isabel wrote this mystery problem. The quotient is multiple of 6. The dividend is multiple of 9. The divisor is a factor of 12.
Marina86 [1]

Answer:

Consider the expression q=\frac{a}{b}. q is called the quotient, a is is the dividend and b is the divisor.

Since q is a multiple of 6, then q has the form q=6k for some integer k.

Since a is a multiple of 9, then a has the form a=9s for some integer s.

Since b is a factor of 12, then if 12 can be expressed of the form 12=c*b, for c an integer. Then b has the form b=\frac{12}{m}

Replacing the preview expression in the initial expression we obtain:

6k=\frac{9s}{\frac{12}{m}}=\frac{9sm}{12}\\6*12k=9sm\\72k=9sm\\72k-9sm=0

Then 72k-9sm=0,\; for \; k,s,m\in \mathbb{Z} is a equation to Isabel's problem.

3 0
2 years ago
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