Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater
Answer:
532m squared is the answer
Step-by-step explanation:
Split the shape into two shapes
one will be a square and the other one a triangle
1) since the length and the width of the square is 18m just Multiply
18x18=324m squared
2) look carefully the width of the square you split is equal to the base of the triangle, so you connect the 18 and the 8 together.
18+8=26m squared
3) Now solve the triangle since you know the height which is 16m squared.
A=lw/2
26x16=416
416 divided by 2 is 208
4) finally just Add
208+324=532m squared
Hopes this helps!
Answer:
84:2 42/1
Step-by-step explanation:
i think
hope ths helps