check the picture below.
so, notice there, the rhombus is really just two triangles, each triangle has a base of 4 units and a height of also 4 units, so simply let's get the area of a triangle and multiply that times 2.
![\bf \stackrel{\textit{area of 2 triangles}}{2\left[\cfrac{1}{2}(4)(4) \right]}\implies 16](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%202%20triangles%7D%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%284%29%284%29%20%5Cright%5D%7D%5Cimplies%2016)
$11.98 : 2 = 5,99 $
$24.95 : 5 = 4,99 $
Second company is better
Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so
3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w
3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2
2x+2x=4x
Answer:
B
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x + 7)² + (y - 5)² = 16 ← is in standard form
with centre = (- 7, 5 ) and r =
= 4 → B
Answer:
1/√5+√3= 1/√5+√3×√5-√3/√5-√3 = √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2} =√5-√3/5-3 =√5-√3/2 ans... Do you satisfied to my given answer
Step-by-step explanation: