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Arisa [49]
3 years ago
14

Write the correct balanced equation for

Chemistry
1 answer:
guapka [62]3 years ago
7 0

The given reaction is between solid iron and aqueous copper (II) bromide to form solid copper and aqueous iron (II) bromide. Iron being more reactive than copper can displace copper ion from its aqueous solution. Therefore, this reaction is an example of single replacement reaction in which Iron displaces copper from an aqueous solution of copper (II) bromide.

Word equation :

Iron (solid)+Copper(II) bromide(aqueous)--->Copper (solid)+Iron (II) bromide (aqueous)

Chemical equation:

Fe(s) +CuBr_{2}(aq)-->Cu(s)+FeBr_{2}(aq)


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A substance registers a temperature change from 20 to 40 to what incremental temperature change does this correspond
ss7ja [257]

<u>Given:</u>

Initial temperature, T1 = 20 C

Final temperature, T2 = 40 C

<u>To determine:</u>

The temperature change

<u>Explanation:</u>

Convert degree C to Kelvin

Temperature in Kelvin = degree C + 273

T1 = 20 + 273 = 293 K

T2 = 40 + 273 = 313 K

Incremental temperature change = T2 - T1 = 313-293 = 20 K

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If you have 12.5g of fluoride and 16.2g of sodium, which is the limiting reactant and how sodium fluoride in grams is your theor
Korvikt [17]

Answer:

F2 is the limiting reactant

27.6 grams of NaF is produced.

Explanation:

Balance the equation first.

2Na+ F2 ---> 2NaF

To find the limiting reactant, solve for how much NaF can be produced with Na and F2

12.5g F2 x (1 mole F2/ 38.00 grams F2)x (2 mole NaF/ 1 mole F2)

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16.2g Na x (1 mole Na/ 22.99 grams Na)x (2 mole NaF/ 2 mole Na)

=0.705 moles NaF

Since F2 produced the least NaF, F2 is the limiting reactant.

Now, to find how much NaF there is, use the moles solved above with F2 as the limiting reactant.

0.658 moles NaF x (41.99 grams NaF/ 1 mole NaF)= 27.6 moles NaF

27.6 moles of NaF would be theoretically produced.

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vladimir2022 [97]

Answer:

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