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Arisa [49]
3 years ago
14

Write the correct balanced equation for

Chemistry
1 answer:
guapka [62]3 years ago
7 0

The given reaction is between solid iron and aqueous copper (II) bromide to form solid copper and aqueous iron (II) bromide. Iron being more reactive than copper can displace copper ion from its aqueous solution. Therefore, this reaction is an example of single replacement reaction in which Iron displaces copper from an aqueous solution of copper (II) bromide.

Word equation :

Iron (solid)+Copper(II) bromide(aqueous)--->Copper (solid)+Iron (II) bromide (aqueous)

Chemical equation:

Fe(s) +CuBr_{2}(aq)-->Cu(s)+FeBr_{2}(aq)


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The primary component of the soda lime used in the experimental chamber (calcium hydroxide) reacts to produce a white precipitat
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Soda lime is a mixture primarily consisting of calcium hydroxide which is used to remove carbon dioxide gas ( CO2) from the surrounding medium.

The reaction of calcium hydroxide with carbon dioxide produces a white insoluble precipitate of calcium carbonate.

The chemical equation for the reaction is given below.

Ca(OH)_{2} + CO_{2} -------->  CaCO_{3} + H_{2} O

From the above equation we can see that the mole ratio of Ca(OH)₂ and CaCO₃ is 1:1 . This can be used as a conversion factor to find moles of CaCO₃ formed during the reaction

2mol[Ca(OH)2] * \frac{1mol[CaCO3]}{1mol[Ca(OH)2]} = 2 mol [CaCO3]

Using molar mass of CaCO3 ( MW = 100.1 g/mol) we can convert moles of CaCO3 to grams.

2mol[CaCO3] * \frac{100.1g[CaCO3]}{1mol[CaCO3]} = 200.2g[CaCO3]

200.2 grams of the precipitate will be produced.

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Để trung hoà 20ml dung dịch HCl 0.1M cần 10ml dung dịch NaOH nồng độ x mol/l . Giá trị của x là
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The question is: To neutralize 20ml of 0.1M HCl solution, 10ml of NaOH solution of concentration x mol/l is required. What is the value of x?

Answer: The value of x is 0.2 M.

Explanation:

Given: V_{1} = 20 mL,   M_{1} = 0.1 M

V_{2} = 10 mL,        M_{2} = x

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times 20 mL = x \times 10 mL\\x = 0.2 M

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