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Kaylis [27]
4 years ago
15

What type of reaction is created by starting a fire by igniting gasoline?

Chemistry
2 answers:
Vladimir79 [104]4 years ago
7 0

Answer:

Oxidation reaction

Explanation:

When flame comes in contact with gasoline in the presence of oxygen, combustion takes place. Oxidation reaction involves reacting oxygen with a compound. To stop fire, we can stop the oxidation process by adding carbon (iv) oxide since it does not support combustion. Hence the reason why CO2 is used to stop flames.

kolezko [41]4 years ago
6 0

Answer:

it a combustion reaction

Explanation:

because fire and gasoline mix together is flammable

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One of the hazards of nuclear explosions is the generation of 90Sr andits subsequent incorporation in place of calcium in bones.
Illusion [34]

Explanation:

Initial mass of the isotope 90-Sr in baby= 1.00 μg

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

N_o = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

t_{\frac{1}{2}} = half life of the isotope  = 28.1 years

\lambda = rate constant

N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

a) Time taken by the sample, t = 18 years

N=1.00 \mu g\times e^{-\frac{0.693}{28.1 years}\times 18 years}

N = 0.6415 \mu g

0.6415 μg  will remain after 18 years.

b) Time taken by the sample, t = 70 years

N=1.00 \mu g\times e^{-\frac{0.693}{28.1 years}\times 70 years}

N = 0.1779\mu g

0.1779 μg  will remain after 70 years.

3 0
3 years ago
WILL GIVE BRAINLIEST!!!
NemiM [27]

1)Is =425·G

2) Is=54· g

6 0
3 years ago
What is the parent isotope when Cl-33 is formed during a beta decay?
zzz [600]

Answer:

33/16 S

Explanation:

In beta decay, the atomic number of the daughter nucleus increases by one unit while the mass of the daughter nucleus remains the same as that of the parent nucleus.

Hence, if we know that a beta decay has occurred, then the parent nucleus must have the same mass as its daughter nucleus but have an atomic number that is less than that of the daughter nucleus by only one unit, hence the answer above.

7 0
4 years ago
When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coeffici
tatuchka [14]

The values of the coefficients would be 4, 5, 4, and 6 respectively.

<h3>Balancing chemical equations</h3>

The equation of the reaction can be represented by the following chemical equation:

ammonia (g) + oxygen (g) ---> nitrogen monoxide (g) + water (g)

  4NH_3(g)     +    5O_2(g)        --->           4NO(g)              +  6H_2O(g)

Thus, the coefficient of ammonia will be 4, that of oxygen will be 5, that of nitrogen monoxide will be 4, and that of water will be 6.

More on balancing chemical equations can be found here: brainly.com/question/15052184

#SPJ1

5 0
2 years ago
Calculate the fraction of lattice sites that are Schottky defects for cesium chloride at 623 oC (this temperature is below the m
Degger [83]

Answer:

5.9 × 10^-6.

Explanation:

In the arrangements of crystal solids there is likely going to be an imperfection or defect and one of the defect or imperfections in the arrangements of solids is known as the Schottky defects. The Schottky defects is a kind of lattice arrangements imperfection that occurs when positively charged ions and negatively charged ions leave their position.

So, let us delve right into the solution of the question. We will be making use of the formula below;

Wb/ W = e^ - c/ 2kT.

Where Wb/ W= fraction of lattice sites, c= energy for defect formation = 1.86 eV, and T = temperature= 623° C= 896 k.

So, Wb/ W = e ^ -1.86/ (2 × 896 × 8.62 × 10^ -5).

Wb/ W= 0.000005896557435956372.

Wb/ W=5.9 × 10^-6.

3 0
3 years ago
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