Answer:
Explanation:
Intake heat, QH = 100 J
output heat, Qc = 20 J
Work, W = 80 J
TH = 100°C = 373 K
Tc = 10°C = 283 K
TH/ Tc = 373 / 283 = 1.318
QH/Qc = 100 / 20 = 5
for a heat engine, those ratios should be same. so temperature is not correct.
Answer:
F = N*μ or F =m*g*μ
Explanation:
The friction force is defined as the product of the normal force by the corresponding friction factor.
When a body is in equilibrium over a horizontal plane its normal force value shall be equal to:
![N = m*g\\where:\\m=mass [kg]\\g=gravity [m/s^2]\\N= normal force [N]](https://tex.z-dn.net/?f=N%20%3D%20m%2Ag%5C%5Cwhere%3A%5C%5Cm%3Dmass%20%5Bkg%5D%5C%5Cg%3Dgravity%20%5Bm%2Fs%5E2%5D%5C%5CN%3D%20normal%20force%20%5BN%5D)
if we simplify this formula more for a balanced body on a horizontal plane, we will have.

Answer:
For the Carnot air conditioner working as a heat pump between 63 and 100°F , It would transfer 3.125 Joules of heat for each Joule of electric energy supplied.
Explanation:
The process described corresponds to a Carnot Heat Pump. A heat pump is a devices that moves heat from a low temperature source to a relative high temperature destination. <em>To accomplish this it requires to supply external work</em>.
For any heat pump, the coefficient of performance is a relationship between the heat that is moving to the work that is required to spend doing it<em>.</em>
For a Carnot Heat pump, its coefficient of performance is defined as:
Where:
- T is the temperature of each heat deposit.
- The subscript H refers to the high temperature sink(in this case the outdoors at 100°F)
- The subscript L refers to the low temperature source (the room at 63°F)
Then, for this Carnot heat pump:

So for each 3.125 Joules of heat to moved is is required to supply 1 Joule of work.