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katrin [286]
3 years ago
7

From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The init

ial speed of the pebble is 6.33 m/s. (a) What is the acceleration (magnitude and direction) of the pebble during the downward motion
Physics
1 answer:
Talja [164]3 years ago
8 0

Answer:

\vec{a} = -(9.8~{\rm m/s^2})\^y

Explanation:

Regardless of the initial velocity of the pebble, the acceleration of the pebble is equal to the gravitational acceleration which is equal to 9.8 m/s2 towards downwards direction.

This can be shown by Newton's Second Law. According to the law, the net force applied on an object is equal to mass times acceleration of that object.

During the downward motion, the only force acting on the pebble is the gravitational force, hence its acceleration is equal to gravitational acceleration.

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Answer : The balanced two-half reactions will be,

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Thus the overall reaction will be,

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Explanation :

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In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The balanced two-half reactions will be,

Oxidation half reaction (anode) : Mg(s)\rightarrow Mg^{2+}(aq)+2e^-

Reduction half reaction (cathode) : Cd^{2+}(aq)+2e^-\rightarrow Cd(s)

Thus the overall reaction will be,

Mg(s)+Cd^{2+}(aq)\rightarrow Mg^{2+}(aq)+Cd(s)

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