I couldn't able to understand ur question , give an example problem
Answer:
Step-by-step explanation:
Given that a machine produces defective parts with three different probabilities depending on its state of repair.
condition Good order Wearing down Needs main Total
Prob 0.8 0.1 0.1 1
Defective 0.02 0.1 0.3
Joint prob 0.016 0.01 0.03 0.056
a) 0.016
b) total = 0.056
c) If not defective from needs maintenance
Prob for not defective = 
From machine that needs maintenance = 0.07
So reqd prob = 
The digit in the tens place is 1.
The digit in the tenths place is 0.
The answer is 6 cm. The mid segment is half of BC
C. Both options A and B will allow him to meet his goal.
Looking at Drake's situation after 4 weeks, he only has $470 saved. By
his original plan, he should have had $500 saved. So he's $30 short of
his goal and has 2 weeks until his originally planned class. If he goes
with option A and takes the later class, he will save an additional $125
which is more than enough to make up the $30 short fall. So option A
will work for him to save enough money for his class. With option B, he
will save $140 for the last 2 weeks of his plan giving him a savings of
$280 for the last 2 weeks. Adding the $470 he's already saved will give
him a total savings of $470 + $280 = $750 which is enough for him to
attend his class. So option B will also allow Drake to attend his
desired class. Both options A and B allow him to meet his goal. Hence,
the answer is "c".
