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hram777 [196]
3 years ago
10

1. If the front of the red car is used as a reference point, how far away is the white van?

Chemistry
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

-26 m

Explanation:

In the image, the original reference point is the front of the black car which is at point 0 meters. The red car is 15 m from the black car while the white van is -21 meters from the black car. If the front of the red car is used as the reference point then the black car would be -15 m from the red car and the white van would be -21 m from the black car, therefore:

Distance of white van from the red car (reference point) = Distance from red car to black car + distance from black car to white van = -15 m + (-21 m)

Distance of white van from the red car (reference point) = -15 m -21 m = -36 m

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6 0
3 years ago
How many grams of ag can be formed from 5.50 grams of ag2o in the equation: 2ag2o (s) → 4ag (s) o2 (g)?
oee [108]

From the given balanced equation we have find out the amount (in gm) of Ag formed from 5.50 gm of Ag₂O.

2Ag₂O(s) → 4Ag (s) + O₂ (g)

We know, molecular mass of Ag₂O= 231.7 g/mol, and atomic mass of Ag= 107.8 g/mol. Given, mass of Ag₂O=5.50 gm. Number moles of Ag₂O=\frac{5.50}{231.7}= 0.0237 moles.

From the balanced chemical reaction we get 2 (two) moles of Ag₂O produces 4 (four) moles of Ag. So, 0.0237 moles of Ag₂O produces \frac{4X0.0237}{2} moles=0.0474 moles of Ag= 0.0474 X 107.8 g of Ag=5.11g Ag.

Therefore, 5.50 g Ag₂O produces 5.11 g of Ag as per the given balanced chemical reaction.


4 0
3 years ago
What happens to particles in diffusion ?
rjkz [21]
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7 0
4 years ago
Read 2 more answers
After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?
FromTheMoon [43]

Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

0,02 moles of N / 0,01 = 2.

Thus, empirical formula is: <em>Mg₃N₂</em>

<em></em>

I hope it helps!

5 0
3 years ago
Which of these activities performed by a chemist is primarily based on an understanding of physics?
Ilia_Sergeevich [38]
<span>predicting the boiling point of a liquid, given its pressure</span>
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3 years ago
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