Answer:
5.95 m
Explanation:
Given that the biggest loop is 40.0 m high. Suppose the speed at the top is 10.8 m/s and the corresponding centripetal acceleration is 2g
For the car to stick to the loop without falling down, at the top of the ride, the centripetal force must be equal to the weight of the car. That is,
(MV^2) / r = mg
V^2/ r = centripetal acceleration which is equal to 2g
2 × 9.8 = 10.8^2 / r
r = 116.64 /19.6
r = 5.95 m
Answer:
b) se duplica
Explanation:
The disk is moving with constant angular velocity, let's call it .
The linear velocity of a point on the disk is given by
where r is the distance of the point from the axis of rotation.
In this problem, the object is moved at a distance twice as far as the initial point, so
Therefore, the new linear velocity is
So, the velocity has doubled, and the correct answer is
b) se duplica
Could u put it in english u can use goggle translation if u do not know how to
Answer:
10.53m/s²
Explanation:
Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:
v is the velocity of the car = 24.5m/s
r is the radius of the track = 57.0m
Substitute the given values into the formula:
Hence the centripetal acceleration of the race car is 10.53m/s²