Swing an arc the length of the radius from the point on the circle
Step-by-step explanation:
When constructing a square inscribed in a circle, you first draw the circle.This is followed by drawing the diameter of the circle.Using a pair of compass, construct a segment bisector of the diameter, and draw the perpendicular bisector to cut the circle at two points .Join the points cut by the diameter and the bisector on the circle to form the inscribed square.
Swinging an arc the length of the radius from the point on the circle will not mark the correct length of the square.The correct length of the square is marked by the points cut by the diameter and the bisector on the circle.
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Construction of inscribed square :brainly.com/question/13152465
Keywords : statement, inscribed square
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For this case we have to if Ali uses
of 2 pounds of clay for a game of 4 bowls we have:
![\frac {3} {8} (2) = \frac {6} {8} = \frac {3} {4}](https://tex.z-dn.net/?f=%5Cfrac%20%7B3%7D%20%7B8%7D%20%282%29%20%3D%20%5Cfrac%20%7B6%7D%20%7B8%7D%20%3D%20%5Cfrac%20%7B3%7D%20%7B4%7D)
Thus, Ali uses
pounds of clay to make a game.
If we want to know how many pounds of clay are used in each bowl, we must divide the previous result by 4, that is:
![\frac {2 * \frac {3} {8}} {4}](https://tex.z-dn.net/?f=%5Cfrac%20%7B2%20%2A%20%5Cfrac%20%7B3%7D%20%7B8%7D%7D%20%7B4%7D)
ANswer:
Part A: ![2 * \frac {3} {8}](https://tex.z-dn.net/?f=2%20%2A%20%5Cfrac%20%7B3%7D%20%7B8%7D)
Part B: ![\frac {2 * \frac {3} {8}} {4}](https://tex.z-dn.net/?f=%5Cfrac%20%7B2%20%2A%20%5Cfrac%20%7B3%7D%20%7B8%7D%7D%20%7B4%7D)
Answer:
9,000 but Idk if that plus is indicating adding or if it is indicating positive
![\qquad\qquad\huge\underline{{\sf Answer}}](https://tex.z-dn.net/?f=%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D)
Let's solve ~
First we have to calculate g (-5) :
![\qquad \tt \dashrightarrow \:x - 8](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3Ax%20-%208)
![\qquad \tt \dashrightarrow \: - 5 - 8](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%20-%205%20-%208)
![\qquad \tt \dashrightarrow \: - 13](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%20-%2013)
Now, let's find f (g (-5)) :
![\qquad \tt \dashrightarrow \: {x}^{2} + 6x](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%20%7Bx%7D%5E%7B2%7D%20%20%2B%206x)
![\qquad \tt \dashrightarrow \:( - 13) {}^{2} + (6 \times - 13)](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%28%20-%2013%29%20%7B%7D%5E%7B2%7D%20%20%2B%20%286%20%5Ctimes%20%20-%2013%29)
![\qquad \tt \dashrightarrow \:169 + ( - 78)](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A169%20%2B%20%28%20-%2078%29)
![\qquad \tt \dashrightarrow \:169 - 78](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A169%20-%2078)
![\qquad \tt \dashrightarrow \:91](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A91)