Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
First, let's factor the equation to make it easier to solve for the intercepts:
f(x) = x² + 12x + 32
f(x) = (x + 8)(x + 4)
To find the x-intercepts of a function, set the y value (f(x)) to 0:
0 = (x + 8)(x + 4)
x = -8, -4
Similarly, to find the y-intercept, set the x values to 0:
f(x) = (0 + 8)(0 + 4)
f(x) = (8)(4)
f(x) = 32
*Note that you can see 32 as the y-intercept in the parabola's original equation
Answer:
William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.
Step-by-step explanation:
Given:
Number of fruits cans = 24
Number of veggies cans = 60
William will have to distribute them in equal bags with equal cans of fruits and vegetables respectively.
For this:
We have to find the GCF (greatest common factor) of 24 and 60.
GCF by listing out the factors method.
Factors of 24 : 
Factors of 60 : 
So,
The greatest common factor of 
and 
is 
.
The number of bags William will used for equal distribution =
Now,
We have to distribute the veggies and fruits in equal number of cans to these bags.
Number of fruits cans used in each bag = 
Number of vegetables can used in each bag = 
We can say that:
William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.
2 hours. She spent 1 hour for math which was half so the total would be 2*1=2.
1/2x=1 /x2
x=2
