Area is 140 and perimeter is 16
Hi, I'm happy to help!
First, we need to find BC. We know, because B is the midpoint of AC, that AB and BC are congruent, or the same length. We are told that AB is 3.
<u>So, BC is 3 also.</u>
Next, we need to find AC. AC is a combination of AB and BC, so, we just add them.
3+3=6
<u>AC is 6.</u>
Finally, we need to find DE. We know that AC and CE are congruent because of this sign: ≅. This means they are the same length. We can then know that CE is 6 also. To find DE we need to take the length of CD away from CE. We know that CD is 2, so now, we subtract.]
6-2=4
<u>DE is 4.</u>
<u></u>
I hope this was helpful, keep learning! :D
10(10x−12)=−9(−9x−2)−5
Step 1: Simplify both sides of the equation.
−10(10x−12)=−9(−9x−2)−5
(−10)(10x)+(−10)(−12)=(−9)(−9x)+(−9)(−2)+−5(Distribute)
−100x+120=81x+18+−5
−100x+120=(81x)+(18+−5)(Combine Like Terms)
−100x+120=81x+13
−100x+120=81x+13
Step 2: Subtract 81x from both sides.
−100x+120−81x=81x+13−81x
−181x+120=13
Step 3: Subtract 120 from both sides.
−181x+120−120=13−120
−181x=−107
Step 4: Divide both sides by -181.
−181x
−181
=
−107
−181
x=
107
181
Answer:
x=
107
181
