Question

A 300.0 mL saturated solution of copper(II) peroidate, Cu(IO4)2, contains .30 grams of dissolved salt. Calculate Ksp.

Answer 1

Answer:

$Ksp=4.9 \times 10^{-8}$

Explanation:

balanced chemical reaction:

$Cu(IO_4)_2 \rightarrow CU^{2+} +2 IO_4^-$

concentration or molarity of Cu(IO4)2= mole/Volume in L

$mole=\frac{mass\, given}{molecular\,weight}$

$mole=\frac{0.30}{445.4}$

$mole=6.74 \times 10^{-4}$

volume= 300 ml=0.3 L

$molarity =\frac{mole}{volume\, in\, L}$

$molarity=2.3\times 10^{-3}$

Solubility means maximum salt which can be dissolved.

lets solubility=S

$[CU^{2+}]=S;$

$[IO_4^-] =2S$

$S=2.3\times 10^{-3}$

$Ksp=S\times(2S)^2$

$Ksp=4.9 \times 10^{-8}$