Answer:
9 moles of ions
Explanation:
Our compound is: CaCl₂(s)
We dissociate it:
CaCl₂(aq) → Ca²⁺ (aq) + 2Cl⁻(aq)
Per 1 mol of chloride, we have 1 mol of calcium cation and 2moles of chlorides, so in total we have 3 moles of ions.
Therefore in 3 moles of chloride, we would have 9 moles of ions (3 . 3)
Answer:
There are 232 calories in the bar
Explanation:
Carbohydrates and protein are both 4 calories per gram, while fat is 9 calories per gram.
![27*4=108\\4*4=16\\12*9=108\\108+108+16=232](https://tex.z-dn.net/?f=27%2A4%3D108%5C%5C4%2A4%3D16%5C%5C12%2A9%3D108%5C%5C108%2B108%2B16%3D232)
This question requires the knowledge of density.
The density of ethyl alcohol = 789 kg m⁻³
The density of water = 1000 kg m⁻³
Density = Mass / Volume
By applying ethyl alcohol,
789 kg m⁻³ = Mass / 0.9 m³
Mass = 710.1 kg
hence the mass of 0.9 m³ ethyl alcohol is 710.1 kg.
Then by applying water,
1000 kg m⁻³ = 710.1 kg / Volume
Volume = 0.7101 m³
= 0.7 m³
hence the equal water volume is 0.7 m³
Answer:
A. for K>>1 you can say that the reaction is nearly irreversible so the forward direction is favored. (Products formation)
B. When the temperature rises the equilibrium is going to change but to know how is going to change you have to take into account the kind of reaction. For endothermic reactions (the reverse reaction is favored) and for exothermic reactions (the forward reaction is favored)
Explanation:
A. The equilibrium constant K is defined as
![K=\frac{Products}{reagents}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7BProducts%7D%7Breagents%7D)
In any case
aA +Bb equilibrium Cd +dD
where K is:
![K= \frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%5BB%5D%5E%7Bb%7D%7D)
[] is molar concentration.
If K>>> 1 it means that the molar concentration of products is a lot bigger that the molar concentration of reagents, so the forward reaction is favored.
B. The relation between K and temperature is given by the Van't Hoff equation
![ln(\frac{K_{1}}{K_{2}})=\frac{-delta H^{o}}{R}*(\frac{1}{T_{1}}-\frac{1}{T_{2}})](https://tex.z-dn.net/?f=ln%28%5Cfrac%7BK_%7B1%7D%7D%7BK_%7B2%7D%7D%29%3D%5Cfrac%7B-delta%20H%5E%7Bo%7D%7D%7BR%7D%2A%28%5Cfrac%7B1%7D%7BT_%7B1%7D%7D-%5Cfrac%7B1%7D%7BT_%7B2%7D%7D%29)
Where: H is reaction enthalpy, R is the gas constant and T temperature.
Clearing the equation for
we get:
![K_{2}=\frac{K_{1}}{e^{\frac{-deltaH^{o}}{R}*(\frac{1}{T_{1}} -\frac{1}{T_{2}})}}](https://tex.z-dn.net/?f=K_%7B2%7D%3D%5Cfrac%7BK_%7B1%7D%7D%7Be%5E%7B%5Cfrac%7B-deltaH%5E%7Bo%7D%7D%7BR%7D%2A%28%5Cfrac%7B1%7D%7BT_%7B1%7D%7D%20-%5Cfrac%7B1%7D%7BT_%7B2%7D%7D%29%7D%7D)
Here we can study two cases: when delta
is positive (exothermic reactions) and when is negative (endothermic reactions)
For exothermic reactions when we increase the temperature the denominator in the equation would have a negative exponent so
is greater that
and the forward reaction is favored.
When we have an endothermic reaction we will have a positive exponent so
will be less than
the forward reactions is not favored.
![{e^{\frac{-deltaH^{o}}{R}*(\frac{1}{T_{1}} -\frac{1}{T_{2}})}}](https://tex.z-dn.net/?f=%7Be%5E%7B%5Cfrac%7B-deltaH%5E%7Bo%7D%7D%7BR%7D%2A%28%5Cfrac%7B1%7D%7BT_%7B1%7D%7D%20-%5Cfrac%7B1%7D%7BT_%7B2%7D%7D%29%7D%7D)
1 mol of formic acid is correct. There are two oxygen atoms in formic acid, compared to just one for the other molecules.