Answer:
The concentration of the solution will be much lower than 6M
Explanation:
To prepare a solution of a solid, the appropriate mass is taken and accurately weighed in a weighing balance and then made up to mark with distilled water.
From
n= CV
n = number of moles m/M( m= mass of solid, M= molar mass of compound)
C= concentration of substance
V= volume of solution
m=120g
M= 40gmol-1
V=500ml
120/40= C×500/1000
C= 120/40× 1000/500
C=6M
This solution will not be exactly 6M if the student follows the procedure outlined in the question. The actual concentration will be much less than 6M.
This is because, solutions are prepared in a standard volumetric flask. Using a 1000ml beaker, the student must have added more water than the required 500ml thereby making the actual concentration of the solution less than the expected 6M.
Explanation:
A compound is defined as follows.
- Compounds are pure substance.
- The atoms bonded in a compound are in specific proportion.
- A compound is formed by chemical combination.
- For a compound, melting point and boiling point is defined.
A mixture is defined as follows.
- Mixtures are impure substance.
- The bonded atoms in a mixture are in any proportion.
- A mixture is formed by physical combination.
- For a mixture, melting point and boiling point is not defined.
On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures as atoms can be bonded in any proportion in a mixture.
The mass/volume percent of solution is 8.69% (m/v).
