<u>Answer:</u> The mass of acetic acid that can be produced is 30.24 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of acetaldehyde = 22.2 g
Molar mass of acetaldehyde = 44 g/mol
Putting values in equation 1, we get:

Given mass of oxygen gas = 12.6 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:

The given chemical equation follows:

By Stoichiometry of the reaction:
2 moles of acetaldehyde reacts with 1 mole of oxygen gas
So, 0.504 moles of acetaldehyde will react with =
of oxygen gas
As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.
Thus, acetaldehyde is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of acetaldehyde produces 2 moles of acetic acid
So, 0.504 moles of acetaldehyde will produce =
of acetic acid
Now, calculating the mass of acetic acid from equation 1, we get:
Molar mass of acetic acid = 60 g/mol
Moles of acetic acid = 0.504 moles
Putting values in equation 1, we get:

Hence, the mass of acetic acid that can be produced is 30.24 grams