Answer:
The cutoff rate that would separate the highest 2.5% of currency A/currency B rates is 1.92.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 1.832
Standard deviation = 0.044
Top 2.5%
95% of the measures are within 2 standard deviation of the mean.
Since the normal distribution is symmetric, this 95% goes from the 50 - 95/2 = 2.5th percentile to the 50 + 95/2 = 97.5th percentile.
The 97.5th percentile is the cutoff for the highest 2.5% of currency A/currency B rates, and it is 2 standard deviations above the mean.
1.832 + 2*0.044 = 1.92
The cutoff rate that would separate the highest 2.5% of currency A/currency B rates is 1.92.
Answer:
y = x - 4
Step-by-Step Explanation:
Perpendicular lines have slopes that are negative reciprocals—multiplying their slopes result in -1.
Given the slope of a line m = -1, then it means that the slope of the other line must be 1 (because multiplying the slope of line 1 (m1 = -1), and the slope of the other line (m2 = 1) results in: -1 × 1 = -1).
Therefore, given the slope of line 2 (m2 = 1), and the point (2, -2), we could plug these values into the slope-intercept form and solve for the y-intercept (b):
y = mx + b
-2 = 1(2) + b
-2 = 2 + b
Subtract 2 from both sides to solve for b:
-2 - 2 = 2 - 2 + b
-4 = b
Therefore, the y-intercept (b) = -4.
Hence, the equation of the perpendicular line is: y = x - 4
Please mark my answers as the Brainliest if you find my explanation helpful :)
How am i supposed to draw it ??
Answer:
![the \: recursive \: formula \: is \\ tn = 6( {4}^{n - 1} )](https://tex.z-dn.net/?f=the%20%5C%3A%20recursive%20%5C%3A%20formula%20%5C%3A%20is%20%5C%5C%20tn%20%3D%206%28%20%7B4%7D%5E%7Bn%20-%201%7D%20%29)
<em>Answer is </em><em>given below with explanations</em><em>. </em>
Step-by-step explanation:
![the \: given \: geometric \: sequence \: is \\ 6, \: - 24, \: 96, \: - 384 \\ the \: first \: term \: is \: 6 \: and \: the \: common \: ratio \: is \: - 4 \\ the \: {n}^{th} term \: of \: the \: geometric \: sequence \: is \\ tn = a {r}^{n - 1} \\ here \: first \: term \:( a) = 6 \\ common \: ratio \: (r) = - 4 \\ on \: substituting \: the \: values \: in \: formula \\ tn = 6( { - 4}^{n - 1} ) \\ the \: above \: mentioned \: formula \: is \: \\ the \: recursive \: formula \: \\ for \: geometric \: sequence.](https://tex.z-dn.net/?f=the%20%5C%3A%20given%20%5C%3A%20geometric%20%5C%3A%20sequence%20%5C%3A%20is%20%5C%5C%206%2C%20%20%5C%3A%20-%2024%2C%20%5C%3A%2096%2C%20%5C%3A%20%20-%20384%20%5C%5C%20the%20%5C%3A%20first%20%5C%3A%20term%20%5C%3A%20is%20%5C%3A%206%20%5C%3A%20and%20%5C%3A%20the%20%5C%3A%20common%20%5C%3A%20ratio%20%5C%3A%20is%20%5C%3A%20%20-%204%20%5C%5C%20the%20%5C%3A%20%20%7Bn%7D%5E%7Bth%7D%20term%20%5C%3A%20of%20%5C%3A%20the%20%5C%3A%20geometric%20%5C%3A%20sequence%20%5C%3A%20is%20%5C%5C%20tn%20%3D%20a%20%7Br%7D%5E%7Bn%20-%201%7D%20%20%5C%5C%20here%20%5C%3A%20first%20%5C%3A%20term%20%5C%3A%28%20a%29%20%3D%206%20%5C%5C%20common%20%5C%3A%20ratio%20%5C%3A%20%28r%29%20%3D%20%20-%204%20%5C%5C%20on%20%5C%3A%20substituting%20%5C%3A%20the%20%5C%3A%20values%20%5C%3A%20in%20%5C%3A%20formula%20%5C%5C%20tn%20%3D%206%28%20%7B%20-%204%7D%5E%7Bn%20-%201%7D%20%29%20%5C%5C%20the%20%5C%3A%20above%20%5C%3A%20mentioned%20%5C%3A%20formula%20%5C%3A%20is%20%5C%3A%20%5C%5C%20the%20%5C%3A%20recursive%20%5C%3A%20formula%20%5C%3A%20%5C%5C%20%20for%20%5C%3A%20geometric%20%5C%3A%20sequence.)
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>
The correct answer to the first question would be the statement 'A protractor and ruler are used to take accurate measurements'. The protractor and the ruler can be used to construct polygons and parallel lines interchangeably.
The correct answer to the second question would be 'open the compass to the width of the line and draw two arcs'.